Answer: 
Step-by-step explanation:


We need -9x on the left side, to move it, we must add 9x on both sides.

Done. We have Ax = 9x, By = 1y and C after the equal sign = -6
Principle: divide the correct possibilities by the total nr. of possibilities to find the probability.
6. P(green) = 5 / (7+5+6) = 5/18
7. P(red) = 6 / 18 = 1/3
8. P(not green) = P(red | blue) = (6+7)/18 = 13/18
9. P(HH) = 5/25 = 1/5
10. P(HT) = 16/25
11. P(NOT TT) = P(HH | HT) = (5+16)/25 = 21/25
12. P(HH | TT) = (5+4)/25 = 9/25
13. P(5) = 1/6. P(H) = 1/2. P(5 & H) = 1/6*1/2 = 1/12. If you draw all the possibilities, you'll find there are 12. One of them is 5 & Heads.
Since you know the area and the width, you can divide the area by the width to find the length. This gives you a length of 110 yards. To find the perimeter of the soccer field, you would add all the side lengths together. Since the width is 70, you would add 70 + 70, along with the length, 110 + 110. This gives you a perimeter of 360.
I can’t see the graph so I’m not sure
Answer:
a) bb, bg, gb, gg
b) 25% probability of getting two green dash eyed children.
c) 50% probability of getting exactly one blue dash eyed child and one green dash eyed child.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this question:
Total of eight outcomes.
a. Construct a similar sample space for the possible eye color outcomes (using b for blue dash eyed and g for green dash eyed) of two children.
bb, bg, gb, gg
b. Assuming that the outcomes listed in part (a) were equally likely, find the probability of getting two green dash eyed children.
Four outcomes.
Of those, in one(gg), you get two green dash eyed children.
1/4 = 0.25
25% probability of getting two green dash eyed children.
c. Find the probability of getting exactly one blue dash eyed child and one green dash eyed child.
In two of those(bg and gb) you get one blue dash eyed child and one green dash eyed child.
2/4 = 0.5
50% probability of getting exactly one blue dash eyed child and one green dash eyed child.