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3 years ago

Computers help eliminate that repetitive of manual task. How can this benefit you in in your overall career

Computers and Technology

2 answers:

kkurt [141]3 years ago

4 0

Answer:-Ensure accuracy in tasks

-Improve productivity and efficciency

Explanation:

andrezito [222]3 years ago

3 0

Continuing advances in technology and automation will be eliminating repetitive work in the offices of the future.

Computer technology has had a tremendous impact upon workers. In some instances, the introduction of computers has improved member working conditions, but, in others, new technology has produced several detrimental effects.

Explanation:

One of the key trends to emerge was that automation, smart machines and artificial intelligence will conduct repetitive work, replacing the need for people to complete these tasks.
Instead of worrying about job losses, executives should be helping to reduce jobs in which AI and machine learning take over boring tasks, while humans spend more time with higher-level tasks.

Here are three ways eliminating repetitive work can boost productivity:

Reduce Dependency on Email and Spreadsheets : Automation tools such as mobile applications, customized portals and project management tools eliminate the time spent checking and responding to emails and updating spreadsheets to reflect work progress. With automated tools, managers and their teams can post progress or project information on an integrated mobile app.
Reduce Mistakes and Injuries : The possibility of human errors, which take more time to correct, is virtually eliminated when tasks are automated. Leaving the monotonous tasks to machines reduces the chance of injuries and allows workers to keep working on more strategic tasks.
Free Employees Time for High-Level Skills : Many of the employees who spend their time undertaking repetitive tasks could actually be better utilized on more complex tasks.

There are a variety of illnesses that may be caused by repetitive computer work :

Tendonitis : pain and swelling of tendons at the junction between the tendon and its muscle;
Epicondylitis: pain and swelling where the tendons and bone join around the elbow joint, etc

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Given six memory partitions of 100 MB, 170 MB, 40 MB, 205 MB, 300 MB, and 185 MB (in order), how would the first-fit, best-fit,

nlexa [21]

Answer:

We have six memory partitions, let label them:

100MB (F1), 170MB (F2), 40MB (F3), 205MB (F4), 300MB (F5) and 185MB (F6).

We also have six processes, let label them:

200MB (P1), 15MB (P2), 185MB (P3), 75MB (P4), 175MB (P5) and 80MB (P6).

Using First-fit

P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
P2 will be allocated to F1. Therefore, F1 will have a remaining space of 85MB from (100 - 15).
P3 will be allocated F5. Therefore, F5 will have a remaining space of 115MB from (300 - 185).
P4 will be allocated to the remaining space of F1. Since F1 has a remaining space of 85MB, if P4 is assigned there, the remaining space of F1 will be 10MB from (85 - 75).
P5 will be allocated to F6. Therefore, F6 will have a remaining space of 10MB from (185 - 175).
P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using First-fit include: F1 having 10MB, F2 having 90MB, F3 having 40MB as it was not use at all, F4 having 5MB, F5 having 115MB and F6 having 10MB.

Using Best-fit

P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
P2 will be allocated to F3. Therefore, F3 will have a remaining space of 25MB from (40 - 15).
P3 will be allocated to F6. Therefore, F6 will have no remaining space as it is entirely occupied by P3.
P4 will be allocated to F1. Therefore, F1 will have a remaining space of of 25MB from (100 - 75).
P5 will be allocated to F5. Therefore, F5 will have a remaining space of 125MB from (300 - 175).
P6 will be allocated to the part of the remaining space of F5. Therefore, F5 will have a remaining space of 45MB from (125 - 80).

The remaining free space while using Best-fit include: F1 having 25MB, F2 having 170MB as it was not use at all, F3 having 25MB, F4 having 5MB, F5 having 45MB and F6 having no space remaining.

Using Worst-fit

P1 will be allocated to F5. Therefore, F5 will have a remaining space of 100MB from (300 - 200).
P2 will be allocated to F4. Therefore, F4 will have a remaining space of 190MB from (205 - 15).
P3 will be allocated to part of F4 remaining space. Therefore, F4 will have a remaining space of 5MB from (190 - 185).
P4 will be allocated to F6. Therefore, the remaining space of F6 will be 110MB from (185 - 75).
P5 will not be allocated to any of the available space because none can contain it.
P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using Worst-fit include: F1 having 100MB, F2 having 90MB, F3 having 40MB, F4 having 5MB, F5 having 100MB and F6 having 110MB.

Explanation:

First-fit allocate process to the very first available memory that can contain the process.

Best-fit allocate process to the memory that exactly contain the process while trying to minimize creation of smaller partition that might lead to wastage.

Worst-fit allocate process to the largest available memory.

From the answer given; best-fit perform well as all process are allocated to memory and it reduces wastage in the form of smaller partition. Worst-fit is indeed the worst as some process could not be assigned to any memory partition.

8 0

4 years ago

Consider a pipelined processor with just one level of cache. assume that in the absence of memory delays, the baseline cpi of th

babunello [35]

Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.

8 0

2 years ago

Which of the following is based on the visibility and location of an object’s features?

grandymaker [24]

Answer:

The answer is Lines.

Explanation:

A visible line, or object line is a thick continuous line, used to outline the visible edges or contours of an object. A hidden line, also known as a hidden object line is a medium weight line, made of short dashes about 1/8” long with 1/16”gaps, to show edges, surfaces and corners which cannot be seen.

7 0

3 years ago

What is the process called that determines how bits are represented on the medium?

Bad White [126]

The process that determines how bits are represented on the medium is called encoding. It is the process of converting a certain data into a particular format that is required for a certain processing need like program execution, data transmission or file conversion.

3 0

3 years ago

An open system consists of nonproprietary hardware and software based on publicly known standards that allows third parties to c

kolezko [41]

Answer:

The answer is "Option D".

Explanation:

A system or a group of components that communicate with your environment through the sharing of resources, materials, and knowledge with a view to system regeneration and development is known as an Open system. In other words, we can say that it is a system that includes a non-proprietary hardware and advert-based software which enables third parties to add or interact with products to plug in the system and It is freely available on the internet. In this question, the incorrect options can be described as follows:

In option A, The management system is used by an organization. It is a paid system that's why it is not correct.

In option B, This system enables users in online communities and evaluates one another that's why it is not correct.

In option C, This type of system provides resources for upgrade user knowledge. It is a paid system that's why it is not correct.

6 0

3 years ago