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steposvetlana [31]
3 years ago
13

A horse had 4 1/5 scoops of oats in his bucket. He ate 2 1/2 scoops of oats. How many scoops of oats were left in his bucket ?

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0

He has 1 7/10 scoops of oats left in his bucket.

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You can buy 5 oranges for $2.50. What is the unit rate for 1 orange? How much would 8 oranges cost?
lions [1.4K]

Answer:

Step-by-step explanation:

You have to divide 5 by 2 to find the unit rate.

5/2= 2.5

Hope this helps.

5 0
2 years ago
Graph Data ALG 2 Please Help!
Sergio039 [100]

Answer:

1.  Figure 3

2. 2881.4 cm³

Step-by-step explanation:

The graph in figure 3 has a curve that fits the data best because it captures most of the points unlike the other two curves.

The curve in figure 3 has the equation;

y=-16.9x^2 +430x+523

2.

When using x=8, substitute the value of x in the equation with 8 to get

y = -16.9*64 + 430*8 + 523

y= 2881.4

= 2881.4 cm³

5 0
3 years ago
If there is an 10+ lax<br> on a $25 pair of pants<br> what is the tax<br> amount?
lesya692 [45]

Answer:

A 6% sales tax.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Can someone help me for this question please? Why I got wrong answer. ASAP!!!
Snowcat [4.5K]

Answer:

a=8.06

A=29.74

B=60.26

Step-by-step explanation:

This is a right angled triangle and Pythagoras theorem is to be obeyed.

To get c, we follow the Pythagoras rule that says

Hyp² = Opp² + Adj²

c= Hypotenuse

c²= a² + b²

c² = 4² + 7²

c² = 65

c = √65 = 8.06

For angle A,

the opposing side to the angle = a = 4

The adjacent side to the angle = b = 7

Following trigonometry rule.

Tan A = opp/adj

Tan A = 4/7

A = Tan–¹(4/7)

A = 29.74°

For angle B,

Opposing side = 7

Adjacent side = 4

Tan B = 7/4

B = Tan-¹(7/4)

B = 60.26°

5 0
3 years ago
2 factors that add to 6 but multiply to 60
hodyreva [135]

Answer:

The short answer is there isn’t.

Start by writing each of these as an expression:

x * y = 60

x + y = 7

Next, solve each for the same variable; in this case, y:

(x * y) / x = 60 / x

.: y = 60 / x

(x + y) - x = 7 - x

.: y = 7 - x

Next, replace y of the second expression to the first

y = 60 / x & y = 7 - x

.: 7 - x = 60 / x

Now, solve for x:

(7 - x) * x = (60 / x) * x

.: x * 7 - x^2 = 60

This is quadratic, so write it in the form of ax2 + bx + x = 0

(-1)x^2 + (7)x + (-60) = 0

.: a = -1, b = 7, c = -60

Finally solve for b:

x = (-b +- sqrt(b^2 - 4*a*c)) / 2a

.: x = (-7 +- sqrt(7^2 - 4*-1*-60)) / (2 * -1)

.: x = (-7 +- sqrt(49 - 240)) / -2

.: x = (-7 +- sqrt(-191)) / -2

The square root of a negative value is imaginary and thus there’s no real answer to this problem.

8 0
2 years ago
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