Answer:
The two compounds that correspond to waste products of cellular respiration are H₂O and CO₂.
Explanation:
The cellular metabolic waste products, specifically from cellular respiration are water (H₂O) and carbon dioxide (CO₂), from the oxidation of glucose into energy.
The process of <u>cellular respiration occurs in the mitochondria of eukaryotic cells and consists of a series of chemical reactions</u> where, from a glucose molecule, energy is obtained in the form of ATP molecules.
Obtaining H₂O and CO₂ from glucose can be summarized with the schematic reaction:
<em>C₆H₁₂O₆ + 6O₂ → 6H₂O + 6CO₂</em>
This summary indicates that a glucose molecule, when oxidized, produces as waste 6 molecules of water and 6 molecules of carbon dioxide. To reach this process all the reactions of the oxidative phosphorylation occur and 24 molecules of ATP are obtained for each molecule of glucose.
For the other options it is important to mention that:
- <em><u>C₆H₁₂O₆</u></em><em> is the substrate from which cellular respiration takes place.
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- <em><u>ATP </u></em><em>is the final product of cellular respiration, translated into energy to be used by the cell.</em>
Answer: A) ice cores can be obtained in Antarctica, mountain glaciers, and Greenland. They are also sharp/drilled glaciers. B) ice cores can be collected anywhere to study regional climate, they also hold a record of what our planet was like hundreds of thousands of years ago.
Explanation:
Sister chromatids remain together in Anaphase I of meiosis due to the presence of cohesin complexes protected by the protein shugoshin.
<h3>What happens during Anaphase of meiosis?</h3>
- The anaphase of meiosis differs from that of mitosis.
- In meiosis, a specific cohesin complex is formed which is different from the cohesion proteins of mitosis.
- During the S phase, this complex is formed at the centromere of sister chromatids.
- At the start, cohesion complex is present throughout the chromosome arms and helps in the formation of synaptonemal complex joining the two homologs.
- However during Anaphase I of meiosis, the cohesion molecules are cleaved by separase in the arms region resulting in separation of homologous chromosomes.
- But the cohesin complexes at the centromeres of the sister chromatids is well protected by shugoshin protein which blocks the action of separase.
- Therefore the sister chromatids remain attached during the Anaphase I.
- At the end of metaphase II, the cohesin molecules at the centromeres lose the protection of shugoshin protein.
- Therefore, the separase proteins are able to cleave the cohesin complex, which allows the sister chromatids to separate at Anaphase II.
Learn more about meiosis I here:
brainly.com/question/8253366
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