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djyliett [7]
4 years ago
8

Given cos(A) = −12/13, with A in quadrant II, and tan(B) = 3/4, with B in quadrant III, which of these is sin(A+B)?

Mathematics
1 answer:
iren2701 [21]4 years ago
6 0
Sin(A+B) = 16/65 see photo for solution

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I need to answer and explain
nignag [31]

Answer:

parallel

Step-by-step explanation:

Solve both equations for y to make it easier to compare them.

2x - 5y = 0 ↔ 5y = 2x, or y = (5/2)x.

y = (5/2)x - 3

Since the slopes are the same, the two lines are parallel.

8 0
3 years ago
What does this symbol mean "⊥" ?
givi [52]

Answer:

The symbol ⊥ means is perpendicular to

Step-by-step explanation:

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6 0
3 years ago
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Please help its urgent ​
dlinn [17]
Pythagorean theorem: a^2 + b^2 = c^2
a^2 + 16^2 = 65^2
a^2 + 256 = 4225
a^2 = 3969
a = 63
Perimeter: add all sides
63 + 16 + 65 = 144
Solution: 144 feet
3 0
3 years ago
Is the area of the shaded rectangle 6(2−m) or 6(m−2)?<br>Explain how you know.
Rzqust [24]

Answer:

6(2-m)

Step-by-step explanation:

the m could not be times only two so the answer would have been 12-m no matter what you don't add or subtract or times the letter because unless if the number had the same letter!

Hope this helps!! if it doesnt i apalogize!! god bless!! - Natalia

6 0
3 years ago
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Biologists have found that the number of chirps some crickets make per minute is related to temperature. the relationship is ver
aalyn [17]

Answer:

It is 74.24 degrees Fahrenheit when the crickets are chirping 150 times a minute.

Variables x = Chirps and  y = Degrees

y-intercept = 38.24

slope = 0.24

Step-by-step explanation:

As the chirps are 124 times per minute for 68 degrees Fahrenheit we will consider it in (x_1,y_1) = (124,68).

Now when the chirps are 172 times and temperature is 80 degrees we consider it (x_2,y_2) = (172,80).

To find the slope we can use point-slope formula.

Where m is the slope and m=\frac{y_2-y_1}{x_2-x_1} =\frac{80-68}{172-124}= 0.24

To find y-intercept we will plug out the value of slope in y=m(x)+b choosing point (x_1,y_1) = (124,68).

So b=y-m(x) =68-124(0.24) =68-29.76=38.24

And the equation is y=0.24(x)+b

To calculate temperature for 150 chirpings we have to plug x=150 and b=38.24 in our above equation which is in form of y=m(x)+b

y=0.24(x)+b

y=0.24(150)+38.24=74.24\approx 75 degrees Fahrenheit.

Finally we have :

Temperature 74.24 degrees Fahrenheit.

With variables x = Chirps and  y = Degrees

y-intercept = 38.24 and

slope = 0.24

6 0
3 years ago
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