Answer:
In this equation n = 15
Step-by-step explanation:
In order to find this, we first must make each term a base 3. Since 9 is 3 squared, we can change it easily to base 3.
3^5 * 9^5 = 3^n
3^5 * (3^2)^5 = 3^n
3^5 * 3^10 = 3^n
3^15 = 3^n
Now that we have both in simple term of 3 raised to a power, we can eliminate the 3's and see that 15 = n
Solve for x:
x + (x + 2) + (x + 4) = 27
3x + 6 = 27
3x = 27 - 6
3x = 21
3x / 3 = 21 / 3
x = 7
The integers:
x + (x + 2) + (x + 4) = 27
7 + (7 + 2) + (7 + 4) = 27
7 + 9 + 11 = 27
27 = 27
The integers are 7, 9 , 11