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pashok25 [27]
3 years ago
15

Compare and contrast some of these disorders

Biology
1 answer:
lisabon 2012 [21]3 years ago
6 0
Don’t think I have learnt this yet
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Which term describes this example? A child with no freckles has a mother who has freckles and is heterozygous and a father who h
ziro4ka [17]
D. Homozygous dominant because the dad has the dominant allele.
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4 years ago
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If a myostatin protein is not the right shape, it cannot fit correctly into a cells receptor true or false
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<h2>This answer would be false</h2>

Explanation: Myostatin (also known as growth differentiation factor 8, abbreviated GDF8) is a myokine, a protein produced and released by myocytes that acts on muscle cells to inhibit muscle cell growth. In humans it is encoded by the MSTN gene.[6] Myostatin is a secreted growth differentiation factor that is a member of the TGF beta protein family.[7][8]

Therefore, if the myostatin protein is smaller than a microorganism it would be able to fit into the receptor.

Also, it helps me out if I get brainliest because it makes me a higher rank

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3 years ago
The outbreak in spread epidemic diseases such as swine flu are tracked by? A epidemiologist or a sonographer
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An epidemiologist

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3 years ago
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If DNA template reads AGCTTAAGC,what is the nucleotide sequence of corresponding DNA strands
Misha Larkins [42]

Answer:

The nucleotide sequence of a corresponding DNA strand would be TCGAATTCG.

It can be explained with the help of complementary base-pairing nature of the DNA strands that is, the nucleotide bases of the two strands are complementary in nature.

The purines (adenine and guanine) always base-pair with pyrimidines (thymine and cytosine).

More specifically, adenine always base-pair with thymine with the help of two hydrogen bonds and guanine always base-pair with cytosine with the help of three hydrogen bonds.

6 0
3 years ago
The double-stranded DNA molecule of the newly discovered Elradicus libanii has a length of 34 micrometers. How many base pairs a
ddd [48]

Answer:

100 000

Explanation:

The average length of a base pair (bp) is 340 pm [340 × 10^(-12) m]

Length of DNA = No. of bp × length of bp

34 × 10^-6 m = n × 340 × 10^-12 m

n = (34 × 10^-6)/(340 × 10^-12) = 100 000

The DNA molecule contains 100 000 base pairs.

7 0
3 years ago
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