<h2>
Answer:</h2>
The value of t is:
t=48.8889
<h2>
Step-by-step explanation:</h2>
We are asked to solve the linear equation in terms of variable t.
The equation is given by:
Firstly we will solve the parentheses term in the left and right hand side of the equality as follows:
Now we combine the like terms on the left side of equality by:
Now we subtract both side of the equation by 5 to get:
Now on dividing both side of the equation by 0.90 we get:
Hence, the value of t is: 48.8889
Answer:
6xy²z^4
Step-by-step explanation:
![\sqrt[3]{216x^3y^6z^12}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216x%5E3y%5E6z%5E12%7D)
= ∛(6³)(x³)(y³)(y³)(z³)(z³)(z³)(z³) = 6x·y·y·z·z·z·z = 6xy²z^4
Answer:
how can i help you
Step-by-step explanation:
i will help
2/3 of pizza would be the answer
Answer:
Step-by-step explanation:
Given that
Sample size = n = 8: sample mean = 36.5 and s = sample std dev = 7.4 minutes
98% CI using t = (28.7, 44.3) with margin of error as 7.8
Now if sigma = population std dev is known we use Z critical value
Margin of error = 2.33*8.7/\sqrt 8 = 7.167
CI = (36.5 ±7.167)
This is not wider than that used using t distribution
The margin of error of u is ___7.167
98% confidence interval using the standard normal distribution is (29.333__,43.667__)
d)the confidence interval found using the standard normal distrubution is narrower than the confidence interval found using the students t-distribution
