Answer:
0
Step-by-step explanation:
In my opinion, the string won't display because, the intCount was not initialized before you started outputting the "Hi" string. So in order fro you to get the string to appear, the control point or value has to be initialized to maybe 0. then you can start looping from there. And if you are looping from the top or using greater than (>), The loop works best buy subtracting the control value else, you can end up with infinity loop.
First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.
If we need the vertex to be at 
, the equation will contain a 
term.
If we start with 
we have a parabola, concave down, with vertex at and a maximum of 0.
So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be 
We have
Now we only have to fix the fact that this parabola doesn't land at 
, because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want
such that:
Plugging these values gets us
As you can see in the attached figure, the parabola we get satisfies all the requests.
93/4
9/4=2r1
13/4=4r1
10/4=2r2
20/5=4
=23.25
Answer:
20
Step-by-step explanation:
Answer:
The equation for b would be y = 1/2x + 1
Step-by-step explanation:
In order to find this, start by finding two points on the line. We'll use (0,1) and (2, 2). From there we start by finding the slope.
m(slope) = (y2 - y1)/(x2 - x1)
m = (2 - 1)/(2 - 0)
m = 1/2
Now using that, we can plug it, along with a point into point-slope form to get the answer.
y - y1 = m(x - x1)
y - 1 = 1/2(x - 0)
y - 1 = 1/2x
y = 1/2x + 1
, we have
