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Anit [1.1K]
3 years ago
10

Given a = 4, b = -2 and c = 8, evaluate ab - bc. -24 -4 8

Mathematics
1 answer:
Mrac [35]3 years ago
8 0
(4*-2)-(-2*8)=
-8--16=8
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Use the Empirical Rule to determine the percentage of candies with weights between 0.7 and 0.98 gram. ​Hint: x=0.84
Lubov Fominskaja [6]

Using the Empirical Rule, it is found that 95% of the candies have weights between 0.7 and 0.98 gram.

<h3>What does the Empirical Rule state?</h3>

It states that, for a normally distributed random variable:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of  the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Researching this problem on the internet, we have that:

  • The mean is of 0.84.
  • The standard deviation is of 0.07.

Then 95% of the candies have weights between 0.7 and 0.98 gram, as:

  • 0.7 = 0.84 - 2 x 0.07.
  • 0.98 = 0.84 + 2 x 0.07.

More can be learned about the Empirical Rule at brainly.com/question/24537145

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2 years ago
Last week the cost of a tank of gas increased by $1.64 express this increase as a mixed number in simplest form
puteri [66]
1 64/100 reduced equals 1 16/25

8 0
4 years ago
Help
Flauer [41]
A) Measure of Angle L is 67.5. Angle F & Angle L are alternate interior angles.

b) Measure of Angle E is 112.5, because we know that F and H are vertical angles, so therefore they’re congruent. We also know H and E are adjacent, so H + E = 180.

c) Angles E and K are alternate exterior angles. Measure of Angle K is 112.5.

d) Measure of Angle H is 67.5, because we know that Angle F, which is vertical to Angle H, is 67.5. Vertical angles are congruent.

e) Measure of Angle I is 112.5, because Angle I and Angle K are vertical angles.

f) They’re corresponding angles.
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How do you change a fraction into a percent?
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Example:
5/20 x 100 you put whatever fraction your looking for into calculator and multiply by 100
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4 years ago
Circle O has diameter FG and chord FH. Calculate the measure of &lt; HFG if GH = 72°
Angelina_Jolie [31]

Given the figure in the attached image.

Circle O has diameter FG and chord FH.

If arc GH is;

GH=72^{\circ}

we want to find the measure of angle HFG.

Recall that from circle geometry theorems;

"The angle at the center of a circle is twice the angle at the circumference of the circle."

So;

\begin{gathered} 2\times m\measuredangle HFG=m\measuredangle GOH \\ m\measuredangle HFG=\frac{1}{2}m\measuredangle GOH \\ m\measuredangle HFG=\frac{1}{2}GH \end{gathered}

substituting the value of GH;

undefined

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2 years ago
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