Answer:
28 hours
Step-by-step explanation:
Let the number of hours required to:
Tutor = x
Walk the dog = y
If you are scheduled to tutor for 10 hours during the week
x = 10........ Equation 1
You can earn money by tutoring for $8 per hour and by walking dogs for $7.50 per hour. Create and solve an inequality that represents the number of hours you can walk dogs during the week in order to earn at least $290 for the week
$8 × x + $7.50 × y ≥ $290
8x + 7.50y ≥ 290..... Equation 2
We substitute 10 for x in Equation 2
8(10 ) + 7.50y ≥ 290
80 +7.50y ≥ 290
7.50y ≥ 290 - 80
7.50y ≥ 210
y ≥ 210/7.50
y ≥ 28 hours
The number of hours you can walk dogs during the week in order to earn at least $290 for the week is 28 hours
N/100*260=39
260n=3,900
n=3,900/260
=(390*10)/(26*10)
=390/26
=15
39 is 15% of 260.
This expression is equal to 27 (30 + 6). 27*30 + 27*6 = 810 + 162, which is equal to 972.
452÷8= 56.5
56 remainder 5
Answer:
Market price of set = 25.14
Step-by-step explanation:
Given:
Discount percentage = 20%
Service charge = 10%
GST = 7%
Amount pays = 23.54
FInd:
Market price of set
Computation:
Assume;
Market price of set = a
Market price of set after discount = a(1-20%)
Market price of set after discount = 0.80a
Market price of set after discount + (Market price of set after discount)(Service charge) + (Market price of set after discount)(GST) = Amount pays
0.80a + (0.80a)(10%) + (0.80a)(7%) = 23.54
0.80a + 0.08a + 0.056a = 23.54
0.936a = 23.54
a = 25.14
Market price of set = 25.14
