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natali 33 [55]
3 years ago
15

Find the point that splits segment AB in half if point A is located at (4, 3) and point B is located at

Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

2√10

I hope i am right

Step-by-step explanation:

(4, 3)  (-2, 6)\\Let -the-distance-be ; d\\x_1=4\\x_2 = -2\\y_1 =3\\y_2 =6\\d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^{2} }  \\d = \sqrt{(-2-4)^2+(6-4)^{2} } \\d = \sqrt{(-6)^2 +(2)^{2} } \\d = \sqrt{36+4} \\d = \sqrt{40}\\ d = 2\sqrt{10}

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A triangle has side lengths of 10, 11, and 15 . what type of triangle is it?
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Justification:

You can find the angles using the law of cosine:

c^2 = a^2 + b^2 - 2abcos(γ)

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1) cos(γ) = [10^2 + 11^2 - 15^2] / (2*10*11) = - 0.0181818

=> γ = arccos(-0.0181818} ≈ 91°

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