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gulaghasi [49]
3 years ago
7

What is the square root of negative 4

Mathematics
2 answers:
Sav [38]3 years ago
6 0
It's 2<em>i</em>, if you've gotten into imaginary numbers. if you haven't gotten there yet, then you aren't supposed to take the square root of negative numbers!!
Alecsey [184]3 years ago
4 0
Sqrt(-4) = 2i

bc. hope you know that sqrt(-1) = i or i^2 = -1

hope helped 
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Step-by-step explanation:

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WILL GIVE BRAINLYIST DUE IN 2 HOURS
Alja [10]

Answer:

Step-by-step explanation:

Isn’t this mathematics not science

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3 years ago
A car travels 17 miles on one gallon of gas
zmey [24]

When x =170, y =10, when x = 187, y = 1, when x = 204, y = 12, when x = 221, y = 13, when x = 238, y = 14, when x = 255, y = 15, when x = 272, y = 16, when x = 289, y = 17, when x = 306, y = 18, when x = 323, y = 19, when x = 340, y = 20,

Step-by-step explanation:

Step 1; Assume y is the gallons in the tank while x is the range of the car. We need to determine the equation relating the y to the x values in the given coordinates. x is the dependent value whereas y is the independent value i.e. the value of x depends on the value of y.

Step 2; As y increases, x also increases. For every extra gallon in the tank, the car can go another 17 miles. So with y as the amount of gas in the tank in gallons and x as the range of vehicle, we get;

x = 17y, this represents the relation between x and y.

To find the gallons in the tank, y = \frac{x}{17},

For x = 170, y = \frac{170}{17} = 10,

Similarly equating the values we get that when x = 187, y = 11,

when x = 204, y = 12,

when x = 221, y = 13,

when x = 238, y = 14,

when x = 255, y = 15,

when x = 272, y = 16,

when x = 289, y = 17,

when x = 306, y = 18,

when x = 323, y = 19,

when x = 340, y = 20,

8 0
2 years ago
In one city, taxi company A charges $5 plus $0.35/km travelled. Taxi company B charges $3.50 plus $0.50/km.
lions [1.4K]

Answer:

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Step-by-step explanation:

3 0
2 years ago
100 POINTS AND BRAINLIEST
zysi [14]

Answer:

8 square units and \frac{40}{3} square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor \frac{1}{3}, then

\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.

2. Triangles ABC and DBE are similar with scale factor \frac{2}{3}, then

\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.

3. Thus, the area of the quadrilateral DFGE is

A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.

and the area of the quadrilateral ADEC is

A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.

4 0
3 years ago
Read 2 more answers
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