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SashulF [63]
3 years ago
7

A sports stadium has 10000 seats, divided into box seats, lower-deck seats, and upper-devk seats. Box seats sell for 10 dollars,

lower-deck seats sell for 8 dollars, and upper-deck seats sell for 5 dollars.If all the seats are sold, the total revenue for a game is 70000 dollars.The stadium has 4 times as many upper* deckseats as box seats.How many lower-deck seats are in the stadium?
Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Answer:

Number of box seats = 1000

Number of lower deck seats = 5000

Number of upper deck seats = 4000

Step-by-step explanation:

Let number of box seats = x

Let number of lower deck seats = y

Let number of upper deck seats = z

As per question statement:

x+y+z=10000 ...... (1)

Cost for box seat = $10

Cost for x box seats = 10x

Cost for lower deck seat = $8

Cost for y lower deck seats = 8y

Cost for lower deck seat = $5

Cost for z lower deck seats = 5z

As per question statement:

10x+8y+5z=70000 ..... (2)

z = 4x ..... (3)

Putting value of y in (1) and (2):

x+y+4x=10000\\\Rightarrow 5x+y=10000 ....... (4)

10x+8 y+5\times 4x=70000\\\Rightarrow 30x+8y=70000 ..... (5)

8 \times (4) - (5):

10x =10000

\Rightarrow x = 1000

By (3):

z = 4000

Now, by equation (1):

y = 5000

Number of box seats = 1000

Number of lower deck seats = 5000

Number of upper deck seats = 4000

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