Let x be the 1st odd number, and x+2 the second odd consecutive number:
(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1
x² + 2x = 12x +12 - 1
And x² - 10x - 11=0
Solve this quadratic expression:
x' = [+10 +√(10²- 4.(1)(-11)]/2 and x" = [+10 -√(10²- 4.(1)(-11)]/2
x' = [10 + √144]/2 and x" = [10 - √64]/2
x' = (10+12)/2 and x" = (10-12)/2
x = 11 and x = -1
We have 2 solutions that satisfy the problem:
1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity
3^3. if you're simplifying then you keep the base the smae but add the exponents since you are "multiplying" the bases
93, 94, 95, 89, 85, 82, 87, 85, 84, 80, 78, 78, 84, 87, 90.
artcher [175]
Answer:
86 is the mean and the median is 85
Step-by-step explanation:
To calculate the mean all u gotta do is add all the numbers then divide by how many numbers there is and to calculate the median all u gotta do is put them in order 78-95 then mark 1 on each side til you reach the middle and the number in the middle is the answer.
-2 + 3(4x - 3) = 16
-2 + 12x - 9 = 16
-11 + 12x = 16
-11 + 11 + 12x = 16 + 11
12x = 27
12x/12 = 27/12
X = 2 3/12
X = 2 1/4
Answer: 8000?
Step-by-step explanation:
If your asking the area of his land, 800 yards
