DDR memory is 64-bit so that means that it is 64
Answer:
See explaination
Explanation:
MinMax.java
import java.util.*;
public class MinMax
{
static void MinMax(int[] arr)
{
int Min=arr[0]; // initializinf min and max with 1st value of array
int Max=arr[0];
for(int i=0;i<arr.length;i++) // iterating loop only once
{
if(arr[i]>Max) // checking max value
{
Max=arr[i];
}
if(arr[i]<Min) // checking min value
{
Min=arr[i];
}
}
System.out.println("Min Number is "+Min); //printing min value
System.out.println("Max Number is "+Max); //printing max value
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter N value: "); // taking n value
int n=sc.nextInt();
int[] arr=new int[n];
System.out.println("Enter N elements:"); // taking n elements into array
for(int i=0;i<n;i++)
{
arr[i]=sc.nextInt(); // each element into the array
}
MinMax(arr); // calling MinMax() method.
}
}
Answer:
This is the location where a document or a portion of another document was retrieved. reference: computerhope.com
In C, you deal with a string always via a pointer. The pointer by itself will not allocate memory for you, so you'll have to take care of that.
When you write char* s = "Hello world"; s will point to a "Hello world" buffer compiled into your code, called a string literal.
If you want to make a copy of that string, you'll have to provide a buffer, either through a char array or a malloc'ed bit of memory:
char myCopy[100];
strcpy(myCopy, s);
or
char *myCopy;
myCopy = (char*)malloc( strlen(s) + 1 );
strcpy(myCopy, s);
The malloc'ed memory will have to be returned to the runtime at some point, otherwise you have a memory leak. The char array will live on the stack, and will be automatically discarded.
Not sure what else to write here to help you...
