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Travka [436]
2 years ago
8

Solve for the indicated variableX = 5y ( for y )​

Mathematics
1 answer:
Sav [38]2 years ago
4 0

Answer:

y= x/5

Step-by-step explanation:

Divide each side by factors that don't contain the variable.

Hope this helps.

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Rewrite the system of linear equations as a matrix equation AX = B.
iren2701 [21]

Answer:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

Equations:

Eq. 1 : x1 + 2x2 + 5x3 = 5

Eq. 2 : x1 + x2 + x3 = 6

E1. 3 : 4x1 + 6x2 + 5x3 = 7

Coefficients for x1 ; x2 ; x3

From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

From eq. 3 : 4 ; 6 ; 5

So matrix A is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

And the vector of vriables (X) is:

\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

Now we can find the resulting vector (B) using the 'resulting values' from each equation:

\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

In conclusion, AX=B is:

\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]

7 0
3 years ago
What is 10 inches divided into 12 equal sections? If you can include work please, Thanx!
satela [25.4K]
Wouldn't you just do 10 divided by 12
4 0
3 years ago
What is a21 of the arithmetic sequence for which a7=−19 and a10=−28? A. -35 B. 35 C. -58 D. -61
shepuryov [24]

Answer:

a21 = -61

Step-by-step explanation:

a_{n}=a_{1}+(n-1)d

-19=a_{1}+(7-1)d

-28=a_{1}+(10-1)d (subtract to eliminate a₁)

9 = -3d

d = -3

-19 = a₁ + (6)(-3)

-1 = a

a21 = -1 + (21 - 1)(-3)

= -61

8 0
3 years ago
Read 2 more answers
Harmonic mean between x and y is
Komok [63]

Harmonic mean between two positive numbers x and y, The simplified formula is \boxed { \mathfrak{h = \frac{2 \times x \times y}{(x + y)}  }} I.e. you need to double the product of x and y then divide it by the sum of x and y...~

4 0
2 years ago
Read 2 more answers
Solve............... the system
nadezda [96]
5y=-25,
y=-5
correct answer (1,-5)
7 0
3 years ago
Read 2 more answers
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