Question

Solve the system of linear equations 3x-y=10 2x+y=5

Answer 1

Answer:

The solution for the system of linear equations 3x-y=10  and 2x+y=5 is x=3 y= -1

Solution:

Given that two linear equations are 3x-y = 10 and 2x + y = 5

We have to find the values of “x” and “y”

Let us consider 3x – y =10 ---- eqn 1

2x + y = 5 --- eqn 2

From eqn 1 , rearranging the terms we get

y = 3x-10  --- eqn 3

By substituting the value of “y” from eqn 3 into eqn 2 we get,

2x + 3x – 10 = 5

On solving above expression, 5x – 10 = 5

5x = 15

x = 3

Substitute the value of “x” in eqn 1 to obtain “y” value

3(3) – y = 10

9 – y = 10

y = 9-10 = -1

Hence the solution for the system of linear equations 3x-y=10  

and 2x+y=5 is x=3 and y= -1