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3 years ago

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I=$26.25I=$26.25, P=$500P=$500, t=18 t=18 months

1 answer:

Travka [436]3 years ago

7 0

Next time, please include the directions for the problem you post. Here it appears that you have given the values of I, P and t two times each.
Unfortunately, I have to guess what you're looking for.

Assuming that I=$26.25 is the interest earned on Principal P=$500, and that t is the length of time over which the Principal earns interest,

I=Prt. With I, P and t given, it's obvious that our job is to find the annual interest rate, r. So, from I=Prt, we get

$26.25 = $500 (r) (1.5 years) Solve this for the interest rate, r.
Express r both as a decimal fraction and as the equivalent percentage.

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3 years ago

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3 years ago

In 1990 the average family income was about $ 39 , 000 , and in 2010 it was about $ 70 , 768 . Let x = 0 represent 1990, x = 1 r

iren2701 [21]

Answer:

<em /> $f(x) = 1588.4x + 39000$ <em />

$f(15) = 62826$

Step-by-step explanation:

Given

In 1990; Income= $39000

In 2010; Income= $70768

Solving (a): An equation in form of f(x) = ax + b

First, we need to determine the slope, a

$a = \frac{y_2 - y_1}{x_2 - x_1}$

Taking y as income and x as year index.

When x = 0; y = 39000

When x = 20; y = 70768

Substitute these values in the above formula

$a = \frac{70768 - 39000}{20 - 0}$

$a = \frac{31768}{20}$

$a = 1588.4$

Next, is to determine the formula using:

$y - y_1 = a(x - x_1)$

<em>Considering :When x = 0; y = 39000, we have</em>

<em /> $y - 39000 = 1588.4(x - 0)$ <em />

<em /> $y - 39000 = 1588.4x$ <em />

<em>Make y the subject of formula</em>

<em /> $y = 1588.4x + 39000$ <em />

<em />

<em>Express y as a function of x</em>

<em /> $f(x) = 1588.4x + 39000$ <em />

Solving (b): Income in 2005

<em>In 2005, x = 15</em>

So:

$f(x) = 1588.4x + 39000$ becomes

$f(15) = 1588.4 * 15 + 39000$

$f(15) = 62826$

3 0

3 years ago