All categories

3 years ago

What is the volume? ___ cubic inches

Mathematics

1 answer:

borishaifa [10]3 years ago

5 0

Answer:

<h2>224 cubic inches</h2>

Step-by-step explanation:

It's a prism.

The formula of a volume of a prism:

$V=BH$

B - area of a base

H - height

We have a triangle in the base.

The formula of an area of a triangle:

$A=\dfrac{bh}{2}$

b - base

h - height

We have b = 4in, h = 7in.

Substitute:

$B=\dfrac{(4)(7)}{2}=\dfrac{28}{2}=14\ in^2$

Put the value of a base B = 14 in² and the height H = 16 in to the formula of a volume:

$V=(14)(16)=224\ in^3$

You might be interested in

Please help…

tino4ka555 [31]

−

3.77

−

3.8

The natural numbers are:

The whole numbers are:

The integers are:

−

The rational numbers are:

−

3.77

−

3.8

The irrational number is:

−

7 0

3 years ago

Write the fact family. for 6, 4, 24

GarryVolchara [31]

$4 \times 6 = 24 \\ 6 \times 4 = 24 \\ 24 \div 6 = 4 \\ 24 \div 4 = 6$
That's it :3

8 0

3 years ago

Read 2 more answers

A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo

djverab [1.8K]

Answer:

a) $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) $31690.7 g/L$

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is $\frac{dy}{dt}=R_{i}-R_{o}$ , where $R_{i}$ is the rate of salt entering and $R_{o}$ is the rate of salt going outside.

Then we have, $R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}$ , and

$R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}$

So we obtain. $\frac{dy}{dt}=4000-\frac{2y}{25}$ , then

$\frac{dy}{dt}+\frac{2y}{25}=4000$ , and using the integrating factor $e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}$ , therefore $(\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}$ , we get $\frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}$ , after integrating both sides $y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C$ , therefore $y(t)= 50000 +Ce^{\frac{-2t}{25}}$ , to find $C$ we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions $y(0)=10$ , so $10= 50000+Ce^{\frac{-0*2}{25}}$

$10=50000+C\\C=10-50000=-49990$

Finally we can write an expression for the amount of salt in the tank at any time t, it is $y(t)=50000-49990e^{\frac{-2t}{25}}$

b) The tank will overflow due Rin>Rout, at a rate of $80 L/min-40L/min=40L/min$ , due we have 500 L to overflow $\frac{500L}{40L/min} =\frac{25}{2} min=t$ , so we can evualuate the expression of a) $y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7$ , is the salt concentration when the tank overflows

4 0

4 years ago

A cookie jar contains four oatmeal raisin, one sugar, nine chocolate chip, and six peanut butter cookies. If one is chosen at ra

Shtirlitz [24]

Answer:

chocolate chips

Step-by-step explanation:

The p denotes here the probability which is given below;

Given that

There is 4 oatmeal raisin

1 sugar

9 chocolate chips

And, 6 peanut butter cookies

So based on the above information, the probability when the one is chosen would be of chocolate chips as it contains the hight value in the cookie jar

So the same is to be selected

6 0

3 years ago

the mean of normally distributed test scores is 80 and the standard division is 5. If there are 186 test scores in the data samp

Marizza181 [45]

Answer:

Step-by-step explanation:

score 75 is one standard dev below the mean ====>to the mean encompasses approx 34% of scores

.34 * 186 = 63

5 0

2 years ago