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Lady_Fox [76]
3 years ago
11

Which big these flags will have the greatest area? Why?

Mathematics
1 answer:
svetoff [14.1K]3 years ago
6 0
<h2><u><em>Question 1:</em></u></h2>

The area of flag b is the greatest.

<u><em>Explanation:</em></u>

Area of triangle = \frac{1}{2}base*height

Area of parallelogram = base * height

<u>For flag A:</u>

It is a triangle with base = b and height = a

Area of flag A = \frac{1}{2}a*b square units

<u>For flag B:</u>

It is a parallelogram with base = a and height = b

Area of flag B = a*b square units

<u>For flag C:</u>

It is a triangle with base = b and height = a

Area of flag C = \frac{1}{2}a*b square units

<u>From the above, we can conclude</u> that the area of the parallelogram (flag B) is the greatest

<h2><u><em>Question 2:</em></u></h2>

The perimeter of flag C is shorter than that of flag A

<em><u>Explanation:</u></em>

Perimeter is the sum of the three sides of the figure

<u>For flag C:</u>

The three sides are given as a, b and c

Therefore, perimeter of flag c = a + b + c units

<u>For flag A:</u>

We are given two sides as b and c and we are given that the height is a

We know that in the given flag, the third side (the unknown slant one) will be longer than the height of the height of the triangle

Therefore, the third side = a + k where k is a constant

Therefore, perimeter of flag A = a + b + c + k units

<u>From the above, we can conclude that</u> the perimeter of flag C is shorter

Hope this helps :)

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The question seem incomplete;

The full question is

<em>Which expression is equivalent to 4√6/3√2 </em>

<em></em>

Given

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