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Semenov [28]
3 years ago
10

A scale drawing of a living room is shown below 5.5 inches and 3 inches scale 1:30 what is the area of the actual living room? R

ound your answer to the nearest whole number
Mathematics
1 answer:
Ostrovityanka [42]3 years ago
7 0

Answer:

<em>14850 inches</em>

Step-by-step explanation:

The complete question is...

A scale drawing of a living room is shown below:

A rectangle is shown. The length of the rectangle is labeled 5.5 inches. The width of the rectangle is labeled 3 inches. The scale is 1 to 30.

What is the area of the actual living room in square feet? Round your answer to the nearest whole number.

The ratio of the scale = 1:30

This means that the dimensions of the drawing has been reduced to 1/30 of the actual building's dimensions.

We first scale up the drawing to 30 times to get the dimensions of the actual building.

The length on the drawing = 5.5 inches

The real length of the actual building = 5.5 x 30 = 165 inches

The width of the drawing = 3 inches

The width of the actual building = 3 x 30 = 90 inches

The area of the actual building = length x width

==> 165 x 90 = <em>14850 inches</em>

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Answer:

The inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}

Step-by-step explanation:

The inner function is the one we apply the outer function to.

So

y = \tan{\pi x}

We apply the outer function tangent to \pi x.

So, the inner function is u = \pi x.

The outer function is f(u) = \tan{u}.

The derivative of a compositve function

y = f(u) in which u = g(x) is given by the following function.

y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

So

f(u) = \tan{u}

f^{\prime}(u) = \sec^{2}{u}

u = g(x) = \pi x

g^{\prime}(x) = \pi

So

y^{\prime} = f^{\prime}(u)*g^{\prime}(x)

\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}

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Step-by-step explanation:

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In the data set below, what are the lower quartile, the median, and the upper quartile?
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The median, upper and lower quartiles of the data set are:

Lower Quartile = 46

Median = 49

Upper Quartile = 90

<h3>What is the Median?</h3>

The center value or middle value of a data set is the median.

<h3>What are the Upper and Lower Quartiles?</h3>

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

Upper quartile (Q3) is the center or middle data point of the second half of a data set.

Order the data set given as:

32, 46, 49, 49, 77, 90, 96

Lower Quartile = 32, (46), 49, 49, 77, 90, 96 = 46

Median = 32, 46, 49, (49,) 77, 90, 96 = 49

Upper Quartile = 32, 46, 49, 49, 77, (90,) 96 = 90

Learn more about the Median, Upper and Lower Quartiles on:

brainly.com/question/15572643

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