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bija089 [108]
3 years ago
9

At a benefit concert, nine bands have volunteered to perform but there is only enough time for seven of the bands to play. How m

any lineups are lineups (Simplify your answer. Type an integer or a fraction.)
Mathematics
1 answer:
Harrizon [31]3 years ago
7 0

Answer: Hi, so here you have 9 bands and time fo only 7, then if the order matters, for the first band you have 9 options, for the second you have 8 options (because one of them already played), for the third band you have 7 options, and so on.

the total number of combinations is 9*8*7*6*5*4*3 = 181440 combinations

If the order of the band doesn't matter, then you need to do the combinatory between 9 and 7 is:

\frac{9!}{(9-7)!*7!} = 9*8/(*2) = 36 combinations, that is the same of dividing 181440 by 7!.

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Jessica went shopping for a new watch. She found a watch that was originally priced at $50 on sale for $40. By what percent had
andrezito [222]

Answer:

20%

Step-by-step explanation:

We were given a price at $50 on sale for $40. To get the markdown percentage, take the amount of money you've discounted the merchandise at and divide it by the sales price.

$50 sweaters, you can put them on sale for $40.

50 - 40 = 10

The difference between these two prices is $10.

Now, we need to add the amount of which it was marked down

10 + 10 = 20

Therefore, the watch has been marked down by 20%.

7 0
3 years ago
In △FEG , point H is between points E and F, point J is between points F and G, and HJ¯¯¯¯¯∥EG¯¯¯¯¯ . EH=8 , HF=12 , and FG=30 .
nlexa [21]

Answer:

39

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
f(t) = t^2 + 19t + 601) What are the zeros of the function?Write the smaller t first, and the larger t second.smaller tlarger t2
GalinKa [24]

Quadratic Function

We are given the function

f\mleft(t\mright)=t^2+19t+60

1) Find the zeros of the function

The zeros or roots of f, are found by equating it to 0:

t^2+19t+60=0

The standard representation of a quadratic function is:

f\mleft(t\mright)=at^2+bt+c

where a,b, and c are constants.

Solving with the quadratic formula:

\displaystyle t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

The coefficients can be established by comparing the generic equation with the given equation, thus: a=1, b=19, c=60. Substituting:

\displaystyle t=\frac{-19\pm\sqrt[]{19^2-4(1)(60)}}{2(1)}=\frac{-19\pm\sqrt[]{361-240}}{2}=\frac{-19\pm\sqrt[]{121}}{2}

Operating:

\begin{gathered} t=\frac{-19\pm11}{2} \\ \text{There are two solutions:} \\ t=\frac{-19+11}{2}=-\frac{8}{2}=-4 \\ t=\frac{-19-11}{2}=-\frac{30}{2}=-15 \end{gathered}

The smaller root is -15, the larger root is -4. Answer:

-15

-4

2) The quadratic equation can be also written in vertex form:

y-k=a\mleft(x-h\mright)^2

Where a is the leading coefficient and (h,k) is the vertex.

To find this form, we need to complete squares as follows.

We need to recall this identity:

\mleft(a+b\mright)^2=a^2+2ab+b^2

Comparing the given function, we can see the first term is t=a, the second term should be 2ab=19t, thus b=19/2

To complete the square, we need to add and subtract b^2 as follows:

y=t^2+19t+(\frac{19}{2})^2-(\frac{19}{2})^2+60

Now we apply the identity:

y=(t-\frac{19}{2})^2-\frac{361}{4}+60=(t-\frac{19}{2})^2-\frac{121}{4}

Finally, we add 121/4:

y+\frac{121}{4}=(t-\frac{19}{2})^2

Comparing with the vertex form of the quadratic function:

a=1

Vertex: (19/2,-121/4)

6 0
1 year ago
PLS HELP WILL MARK BRAINLIEST
vovangra [49]

Answer:

1. Given

2. Given

3. Definition of perpendicular lines

4. Definition of midpoint

5. Reflexive property

6. SAS

Step-by-step explanation:

It's correct

8 0
3 years ago
you and four of your nine classmates received an A on your math test, what is the simplest fraction of students that scored an A
alex41 [277]
The simplest fraction is 4/5
8 0
3 years ago
Read 2 more answers
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