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bija089 [108]
3 years ago
9

At a benefit concert, nine bands have volunteered to perform but there is only enough time for seven of the bands to play. How m

any lineups are lineups (Simplify your answer. Type an integer or a fraction.)
Mathematics
1 answer:
Harrizon [31]3 years ago
7 0

Answer: Hi, so here you have 9 bands and time fo only 7, then if the order matters, for the first band you have 9 options, for the second you have 8 options (because one of them already played), for the third band you have 7 options, and so on.

the total number of combinations is 9*8*7*6*5*4*3 = 181440 combinations

If the order of the band doesn't matter, then you need to do the combinatory between 9 and 7 is:

\frac{9!}{(9-7)!*7!} = 9*8/(*2) = 36 combinations, that is the same of dividing 181440 by 7!.

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What is the 100th term in the list?1017243138
Studentka2010 [4]

the sequence starts at 10 and increases by 7 each time, thefore a possible sequence identification is:

\begin{gathered} a_n=7n+3 \\ \text{Let's verify:} \\ a_1=7(1)+3=7+3=10 \\ a_2=7(2)+3=14+3=17 \\ a_3=7(3)+3=21+3=24 \\ \text{and so on} \\ \text{.} \\ \text{.} \\ \text{.} \end{gathered}

Therefore, the 100th term is:

a_{100}=7(100)+3=700+3=703

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1 year ago
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3 years ago
When you flip a biased coin the probability of getting a tail is 0.34. Find the probability of getting a head.
koban [17]

Answer:

If you want to know what the probability is to get at least one Heads, then that is the same as the probability of all the events (100%, or 1) minus the probability of getting all Tails.

There are 100 coins. 99 are fair, 1 is biased with both sides as heads. With a fair coin, the probability of three heads is 0.53=1/8. The probability of picking the biased coin: P(biased coin)=1/100.

Step-by-step explanation:

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You need to solve this for h(t)=0

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