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3 years ago

India has a large coastline which advantageous explain

Geography

1 answer:

Elden [556K]3 years ago

5 0

Answer:

1. It's central location and long coastline enable many countries to pass through India's pore during their sea route

2. major ports on eastern and western coasthelp in import and export of goods from india developing its trade

3. it can also be used to harness wind power

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10. Which breed became prolific when flocks were abandoned due to drought or lack

Volgvan

The correct answer is B. Australian Goat.

Explanation

During the 18th century, Australian settlers brought goats to Australian territory and settled throughout the country. However, after a long drought, the grazing of goats was not profitable, so their owners had to release them, and many of them had previously escaped and had survived drifting out of the dry areas. This caused them to reproduce and increase their population. Therefore, the correct answer is B. Australian Goat.

4 0

3 years ago

Match each country to its region.

AysviL [449]

Answer:

Morocco - Northern Africa

Spain - Europe

Paraguay - South America

Cuba - North America

Explanation:

Sorted by region.

3 0

3 years ago

Which process of sedimentary rock formation occurs last?

Anettt [7]

Erosion, because after the sedimentary rock erodes it will then be deposited as in the form of pebbles or debris, from there it will undergo the process of compaction and cementation only to be eroded again.

6 0

4 years ago

Please answer this fast and here only

Vaselesa [24]

Answer:

1) a) $r_{R,I} = 1150\,m$ , b) $r_{R,II} = 3400\,m$ , c) $r_{R,III} = 2750\,m$ .

2) a) $r_{R,I} = 45,2\,km$ , b) $r_{R, II} = 28,15\,km$ , c) $r_{R,III} = 51,8\,km$ .

Explanation:

The scale factor is defined by the following expression:

$n = \frac{r_{S}}{r_{R}}$ (1)

Where:

$n$ - Scale factor.

$r_{S}$ - Scale distance, in centimetres.

$r_{R}$ - Real distance, in centimetres.

1) If we know that $n = \frac{1}{50000}$ , $r_{S,I} = 2,3\,cm$ , $r_{S,II} = 6,8\,cm$ and $r_{S,III} = 5,5\,cm$ , then the actual distances in metres are:

$r_{R,I} = \frac{r_{S,I}}{n}$

$r_{R,I} = \frac{2,3\,cm}{\frac{1}{50000} }$

$r_{R,I} = 115000\,cm$

$r_{R,I} = 1150\,m$

$r_{R,II} = \frac{r_{S,II}}{n}$

$r_{R,II} = \frac{6,8\,cm}{\frac{1}{50000} }$

$r_{R,II} = 340000\,cm$

$r_{R,II} = 3400\,m$

$r_{R, III} = \frac{r_{S, III}}{n}$

$r_{R,III} = \frac{5,5\,cm}{\frac{1}{50000} }$

$r_{R,III} = 275000\,cm$

$r_{R,III} = 2750\,m$

2) If we know that $n = \frac{1}{50000}$ , $r_{S, I} = 90,4\,cm$ , $r_{S, II} = 56,3\,cm$ and $r_{S,III} = 103,6\,cm$ , then the actual distance in kilometres is: