All categories

2 years ago

∠a and ∠e are ______ angles.

Mathematics

1 answer:

Bess [88]2 years ago

6 0

angle a and angle e are obtuse angles

You might be interested in

Simplify (2^5/3^2)^4

BabaBlast [244]

Answer:

first one on top.

Step-by-step explanation:

3 0

3 years ago

Suppose that a sample of size 100 is to be drawn from a population with standard deviation L0. a. What is the probability that t

NARA [144]

Answer:

The probability that the sample mean will lie within 2 values of μ is 0.9544.

Step-by-step explanation:

Here

the sample size is given as 100
the standard deviation is 10

The probability that the sample mean lies with 2 of the value of μ is given as

$P(| \bar{X}-\mu|$

Here converting the values in z form gives

$P(-2$

Substituting values

$P(-2$

From z table

$P(z\leq 2)=0.9772\\P(z\leq -2)=0.0228\\P(-2\leq z\leq 2)=P(z\leq 2)-P(z\leq -2)\\P(-2\leq z\leq 2)=0.9772-0.0228\\P(-2\leq z\leq 2)=0.9544\\$

So the probability that the sample mean will lie within 2 values of μ is 0.9544.

5 0

3 years ago

Alexander says that 3x + 4y is equivalent to (3)(4) + xy because of any order, any grouping. Is he correct why or why not

snow_lady [41]

Answer:

Alexander is incorrect because the expressions are not equivalent.

Step-by-step explanation:

If the expression is evaluated for any value of x, y; the result will not be same.

For instance, let assume x = 1 and y = 2

3x + 4y = 3 + 4 = 7

(3)(4) + xy = (3)(4) + (1 * 2) = 12 + 2 = 14

So, the expressions are not the same and Alexander is incorrect.

3 0

3 years ago

The students claims that the model accurately describes the motion of the galaxies in the universe what evidence from the model

alexandr402 [8]

Answer: As the dough rises, the distance between the raisins increases, indicating that the galaxies are moving apart.

Step-by-step explanation:

6 0

2 years ago

What is the value of (7 + 2i)(3 - i)?

Harrizon [31]

There are two ways to work this out: normal variables or using "imaginary" numbers.

Normal variables:
$(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}$

Imaginary numbers:
Using the result from earlier:
$21-i-2i^{2}$
Now since $i = \sqrt{-1}$ , then the expression becomes:
$21-i-2i^{2}\\21-i-2(\sqrt{-1})^{2}\\21-i+(-2)(-1)\\21-i+2\\\\23-i$

7 0

3 years ago