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SIZIF [17.4K]
3 years ago
8

Rewrite 4% as a decimal

Mathematics
2 answers:
Svetllana [295]3 years ago
8 0
.04 is 4% converted to a decimal.
Archy [21]3 years ago
3 0
The solution to the above problem is not surprising, since percents, dollars and cents are all based on the number 100. To convert a percent to a decimal, first remove the percent symbol, then move the decimal point two places to the left... SO YOUR ANSWER WILL BE .04
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Part 1
Dmitrij [34]

Answer:

a)  A n  (B' n C') =  {3, 9}.

b) (AUB) n (BUC) = {2,4,5,6,7,8}

Step-by-step explanation:

a)  Rewriting C ; C = {4,5,6,7,8}

B' = {3,5,7,9} and C' = {2, 3, 9}

so (B' n C') = {3, 9}

and A n  (B' n C') =  {3, 9}.

b)  {A U B} = { 2,3,4,5,6,7,8,9} and {B U C} = {2,4,5,6,7,8}

so (AUB) n (BUC) = {2,4,5,6,7,8}

4 0
3 years ago
Kyle bought a sandwich for $4.95, a bag of chips for $2.30, and a drink for $1.10. The tax was $0.65. He gave the cashier $10.00
sweet-ann [11.9K]
Hello!

Add up the costs of everything Kyle purchased and the tax, and then subtract that from $10.

4.95 + 2.30 + 1.10 + 0.65 = 9

10 - 9 = 1

Kyle should have received $1 change.
4 0
3 years ago
Read 2 more answers
Ashley has sold 70% of the 20 candy bars she has to. How many candy bar's does she have left to sell
yawa3891 [41]
She has 6 left.
70%= 0.7
0.7 x 20 = how many she has sold (14)
OR
30%=0.3
0.3 x 20= how many she hasn't sold (6)


4 0
3 years ago
Read 2 more answers
State the excluded value of 60x^3 /12x
Neporo4naja [7]

Answer:

\frac{60 {x}^{3} }{12x}

5 {x}^{2}

8 0
3 years ago
The number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.08
kvv77 [185]

Answer:

a) 44.93% probability that there are no surface flaws in an auto's interior

b) 0.03% probability that none of the 10 cars has any surface flaws

c) 0.44% probability that at most 1 car has any surface flaws

Step-by-step explanation:

To solve this question, we need to understand the Poisson and the binomial probability distributions.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Poisson distribution with a mean of 0.08 flaws per square foot of plastic panel. Assume an automobile interior contains 10 square feet of plastic panel.

So \mu = 10*0.08 = 0.8

(a) What is the probability that there are no surface flaws in an auto's interior?

Single car, so Poisson distribution. This is P(X = 0).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.8}*(0.8)^{0}}{(0)!} = 0.4493

44.93% probability that there are no surface flaws in an auto's interior

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws?

For each car, there is a p = 0.4493 probability of having no surface flaws. 10 cars, so n = 10. This is P(X = 10), binomial, since there are multiple cars and each of them has the same probability of not having a surface defect.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.4493)^{10}.(0.5507)^{0} = 0.0003

0.03% probability that none of the 10 cars has any surface flaws

(c) If 10 cars are sold to a rental company, what is the probability that at most 1 car has any surface flaws?

At least 9 cars without surface flaws. So

P(X \geq 9) = P(X = 9) + P(X = 10)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.4493)^{9}.(0.5507)^{1} = 0.0041

P(X = 10) = C_{10,10}.(0.4493)^{10}.(0.5507)^{0} = 0.0003

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.0041 + 0.0003 = 0.0044

0.44% probability that at most 1 car has any surface flaws

5 0
3 years ago
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