All categories

3 years ago

Find the value of x. The diagram is not drawn to scale. (1 point)

Mathematics

1 answer:

faust18 [17]3 years ago

7 0

I got 45 for this, not sure if it’s right. Hope that helps. :D

You might be interested in

Find the area of a regular hexagon with the given measurement. 48-inch perimeter A = sq. in. the answer is a square root

svp [43]

The area of a regular hexagon is

... A = (3√3)/2×s² . . . . . where s is the side length

Of course, the 6-sided figure will have a side length that is 1/6 of the perimeter.

... s = (48 in)/6 = 8 in

... A = (3√3)/2×(8 in)² = 96√3 in² . . . area of your regular hexagon

5 0

3 years ago

Nina had 17 marbles in a bag. Her mother put a handful of marbles in the bag. When Nina counts her marbles, she discovers she no

Ksivusya [100]

The second equation is correct. Nina initally had 17 marbles in her bag. Her mother placed m marbles into her bag. After counting, she now has 34 marbles. Part of this 34 marbles is already her initial 17 marbles. Therefore, 17 marbles initially + m unknown marbles = 34 marbles. The equation 17 + m = 34 is the answer.

7 0

3 years ago

Calculating Profit Using this table, calculate the profit at each level of bicycle production. One bike: -$ Two bikes: $ Three b

leonid [27]

Answer:

1~30

2~3

3~40

4~70

5~90

6~90

7~80

Step-by-step explanation:

subtract the total revenue from the total cost

8 0

3 years ago

The equation r(t)= (2t)i + (2t-16t^2)j is the position of a particle in space at time t. Find the angle between the velocity and

ankoles [38]

Answer:

The answer is 135 degrees.

Step-by-step explanation:

As we are given the position. If we take the derivative, we get the velocity vector. If we take the derivative again, we find the acceleration vector of the particle.

$r(t)=(2t)i+(2t-16t^{2})j$

$V(t)=2i+(2-32t)j$

$a(t)=-32j$

At time t=0;

$v(t)=2i+2j$

$a(t)=-32j$

As i attach in the picture the angle between the velocity and acceleration vector is $(45+90)=135$ degrees

4 0

4 years ago

A geometric series has second term 375 and fifth term 81 . find the sum to infinity of series .

Eduardwww [97]

Answer: $\bold{S_{\infty}=\dfrac{3125}{2}=1562.5}$

Step-by-step explanation:

a₁, 375, a₃, a₄, 81

First, let's find the ratio (r). There are three multiple from 375 to 81.

$375r^3=81\\\\r^3=\dfrac{81}{375}\\\\\\r^3=\dfrac{27}{125}\qquad \leftarrow simplied\\\\\\\sqrt[3]{r^3} =\sqrt[3]{\dfrac{27}{125}}\\ \\\\r=\dfrac{3}{5}$

Next, let's find a₁

$a_1\bigg(\dfrac{3}{5}\bigg)=375\\\\\\a_1=375\bigg(\dfrac{5}{3}\bigg)\\\\\\a_1=125(5)\\\\\\a_1=625$

Lastly, Use the Infinite Geometric Sum Formula to find the sum:

$S_{\infty}=\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{625}{1-\frac{3}{5}}\\\\\\.\quad =\dfrac{625}{\frac{2}{5}}\\\\\\.\quad = \dfrac{625(5)}{2}\\\\\\.\quad = \large\boxed{\dfrac{3125}{2}}$

7 0

3 years ago