The answer for #2 is A
And the answer for #3 is B
Answer:
27.2mm²
Step-by-step explanation:
Area of a triangle = 
* base * height
Base of this triangle = 8mm
Height = 6.8mm
Area = 
= 4mm * 6.8mm
= 27.2mm²
we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
Answer:
10
Step-by-step explanation:
<h3>Calculating BC</h3><h3>BC = √2^2 + 11^2 </h3><h3>BC = √ 4+121</h3><h3>BC = √ 125 = 11.18</h3>
to find measure of angle C use sinerule
<h3>sinC/C = sinA/A</h3><h3>sinC/2= Sin90/11.18</h3><h3>SinC = 2×1/11.18</h3>
<h3>sinC = 2/11.18</h3><h3>sinC = (0.1788)</h3><h3>C = sin^-1(0.1788)</h3>
<h3>C = 10.305</h3><h3>C = 10 (approximately)</h3>
