Answer:
The domain of function 
is set of all real numbers.
Domain: (-∞,∞)
Step-by-step explanation:
Given:
the domain of both the above functions is all real number.
To find domain of :
Substituting functions 
and 
to find
The product can be written as difference of squares. ![[a^2-b^2=(a+b)(a-b)]](https://tex.z-dn.net/?f=%5Ba%5E2-b%5E2%3D%28a%2Bb%29%28a-b%29%5D)
∴ 
The degree of the function is 2 as the exponent of leading term 
is 2. Thus its a quadratic equation.
For any quadratic equation the domain is set of all real numbers.
So Domain of is (-∞,∞)
I think it’s the number 3 I’m not sure I’m learning this stuff rn I’m getting the hang of it just it’s hard and not hard at the same time
Warning: This might be rough...
First draw it out. Label the angles at the corners of the triangle 60 (definition of equilateral triangles). Now draw a line from the center of the circle to the corner, splitting the corner in half. Label this line R and a corner as 30 degrees. No to find the height of this triangle, you do rsin(30). The base of this triangle is 2rcos(30). Now find the area of this mini triangle (rsin(30)*2rcos(30)/2=r/2*rsqrt(3)/2=r^2sqrt(3)/4). Now multiply this by 3 because you have 3 mini triangles... to get...
<span>r^2 3sqrt(3)/4</span>
Answer:
x+((4 + 1/3))=(-(2 + 5/6))
6x = -43
x≈ -7.166667
Parallel lines will have the same slope
y - y1 = m(x - x1)
slope(m) = 2
origin (0,0)...x1 = 0 and y1 = 0
now we sub
y - 0 = 2(x - 0) <===
