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vredina [299]
3 years ago
14

According to the real rational root theorem, what are all the potential rational roots of f(x)=5x3-7x+11

Mathematics
1 answer:
ololo11 [35]3 years ago
6 0

Answer:

x = -11, -11/5, -1, -1/5, 1/5, 1, 11/5,11

Step-by-step explanation:

The general formula for a third-degree polynomial is

f(x) = ax³ + bx² + cx + d

Your polynomial is  

f(x) = 5x³ + 7x + 11

a = 5; d = 11

p/q = Factors of d/Factors of a

Factors of d = ±1, ±11

Factors of a = ±1, ±5

Potential roots are x = ±1/1, ±1/5, ±11/1, ±11/5

Putting them in order, we get the potential roots

x = -11, -11/5, -1, -1/5, 1/5, 1, 11/5, 11

(There are no rational roots. There is one irrational root and two imaginary roots.)

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If you have a budget of 12% of your monthly income for groceries how much can you spend on groceries if you are 950 bi-weekly
Shalnov [3]
Aloha!
 There is a one step equation for this question and here is how to solve it.
Step 1. Multiply $950 by .12=$114 dollars

 Note: I changed 12% into a decimal by multiplying 12% by 100.  (Or you can just put a decimal in-front of the percent.)

 I hope this helps!:)
6 0
3 years ago
If A= 3x^2+5x-6 and B = -2x^2-6x+7 then A-B equals ​
Ber [7]

Answer:

A-B=x^2-x+1

Step-by-step explanation:

A-B=3x^2+5x-6+(-2x^2-6x+7)

 =3x^2+5x-6-2x^2-6x+7

 =x^2-x+1

5 0
2 years ago
Nelson paid $25.95 for each adult hat and $13.95 for each youth hat he bought. Nelson bought 3 adult hats and 4 youth hats. How
Furkat [3]

Answer:

Step-by-step explanation:

25.95 x 3 = 77.85

13.95 x 4 = 55.8

77.85 + 55.8 = 133.65

5 0
2 years ago
How many 1/3 cubes does it take to fill a box with a width of 2 2/3 inches length 3 1/3 inches and height 2 1/3
Paladinen [302]

Answer:

560

Step-by-step explanation:

I assume 1/3 is the side length of the cubes.

There's two ways to solve this:

1. Find the volume of the box, then divide by the volume of the cubes.

Or 2. Find the number of cubes per each side length, the find the volume in terms of cubes.

Either way, we need to convert the mixed fractions to improper fractions.

W = 2⅔ = (2×3+2)/3 = 8/3 inches

L = 3⅓ = (3×3+1)/3 = 10/3 inches

H = 2⅓ = (2×3+1)/3 = 7/3 inches

Using the first method, the volume of the box is:

V = (8/3 in) (10/3 in) (7/3 in) = 560/27 in³

The volume of a cube is:

V = (1/3 in)³ = 1/27 in³

So the number of cubes in the box is:

(560/27 in³) / (1/27 in³) = 560

Using the second method, the cubes per each side of the box is:

W = (8/3 in) / (1/3 in) = 8

L = (10/3 in) / (1/3 in) = 10

H = (7/3 in) / (1/3 in) = 7

So the number of cubes is:

8 × 10 × 7 = 560

7 0
3 years ago
Part A: Solve P = 4a for a. Show your work. (4 points) Part B: Solve 3c − 5f = 55 for f. Show your work. (6 points)
sergiy2304 [10]
Since we have two unknowns in both equations, the solution will still consists the known.
For the part A
P=4a,
Dividing both sides by 4,
P/4 =a
Therefore, a = P/4

Part B:
3c - 5f = 55
Add 5f on both sides of the equation,
3c-5f+5f=55+5f
3c=55+5f
Now subtract 55 on both sides
5f = 3c - 55
Divide both side of the equation by 5 to get f,
5f/5 = (3c-55)/5
f = (3/5)c - 11
5 0
4 years ago
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