Answer:
20 times
Step-by-step explanation:
The faster swimmer can swim twice the length of the pool in ...
(2·90 ft)/(3 ft/s) = 60 s
The slower swimmer can do it in ...
(2·90 ft)/(2 ft/s) = 90 s
The least common multiple of these times is 180 s = 3 minutes, after which time each swimmer will be back where they started.
A graph of position vs. time shows the swimmers pass 5 times in that 3-minute period. 4 of those are passes when they are going in opposite directions. A 5th pass occurs at one end of the pool, when the faster swimmer passes the slower one going in the same direction.
Since there are 5 passes in each 3-minute period, there are 20 passes in 12 minutes.
The swimmers pass each other 20 times in 12 minutes.
I honestly don’t know but I really need this so I can get my answer as well , good luck though .
Answer: 
Step-by-step explanation:
For this exercise it is important to remember that, by definition, the length of the minor arc can be calculated wih the following formula:

In this case , according to the data given in the exercise, you know that:

Therefore, susbtituting those values into the formula, you get that length of AB is the following:

Answer:
5y-6
Step-by-step explanation: