Answer:
The answer would be A. 1.25
Let X be the first number
there is a 2 numbers distance between each even number eg.2 ,4, 6, 8, etc.
So the 2nd number is X+2
The sum of the 1st and 2nd numbers = 14
X + X+2 =14
2X +2 =14
2X = 14-2
2X = 12
X = 12/2
X = 6
Therefore,
The first number i.e, X = 6
And the second number i.e, X+2 = 6+2 =8
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This is the only positive pair in case of two consecutive numbers if the are even numbers but not consecutive there will be more pairs
12 + 2 = 14
10 + 4 = 14
8 + 6 = 14 (Already found)
<span>I can solve for x and y
A) 2x - 4y = 12
A) 2x = 4y + 12
A) x = 2y + 6
Substituting into B
B) 3* (2y +6) - 5y = 20
B) 6y + 18 -5y = 20
B) y = 2
B) x = 10
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Answer:
4(3+x)
Step-by-step explanation:
If any thing is in the brackets you need to do it first
so if you do 3 + x × 4 it will give yo 4x + 3 or 3 +4x
Answer:
(3,2) I think
Step-by-step explanation:
X= 3
Y=2
3 +2 =5
3-2=1
