Answer:
The odd is zero.
Explanation:
Assuming the Huntington disease allele is represent by b. Nomal allele will be B which is the alternate form.
The genotype of the 25 years old woman will be Bb, since she heterozygote.
The genotype of the husband will be BB, since he's free from the trait.
Crossing both genotypes:
Bb x BB = BB, BB, Bb and Bb.
The genotypes of the offspring will be either BB or Bb. They either free from the trait or heterozygote.
<em>Hence, the odds that the couple will have a child with the disorder is 0. They can only produce heterozygotes or totally normal children.</em>
Answer:
option 1- type 1 are considered insulin dependent
Explanation:
the other options all describe type 2
Answer:
I think Parietal or Temporal
A microscope? Because it like looks at small micro objects.
Answer:
Cell A is laterally being inhibited by other neighbouring cells.
Explanation:
Cell A showing lower activity compare to cell B despite both having high simulation is because Cell A is surrounded by neighbouring cells and these neighbouring cells hinder the action potential of cell A through their numerous activity they perform around cell A.
Therefore they restrain the activities of cell A.