3 years ago

Please help 5% of 2,500m^2 = ?m^2

Mathematics

1 answer:

sineoko [7]3 years ago

6 0

$=0.05\cdot2,500 \text{ m}^2=125\text{ m}^2$

You might be interested in

A number added to itself equals ten

mylen [45]

The answer is going to be five because five plus five is ten!!!

3 0

4 years ago

Read 2 more answers

For z = 2cis 60°, find z4 in rectangular form.

a_sh-v [17]

By DeMoivre's theorem,

$z=2\mathrm{cis}60^\circ\implies z^4=2^4\mathrm{cis}(4\times60)^\circ=16\mathrm{cis}\,240^\circ$
$z^4=16(\cos240^\circ+i\sin240^\circ)$
$z^4=16\left(-\dfrac12-i\dfrac{\sqrt3}2\right)$
$z^4=-8-i8\sqrt3$

5 0

4 years ago

Read 2 more answers

Find the mass of the triangle with vertices (1; 0; 0), (0; 2; 0), (0; 1; 1) if the density function is given by (x; y; z)

Luda [366]

Answer:

$=\frac{17}{3}$

Step-by-step explanation:

Density of a function is $\rho(x,y)=x^{2} +y^{2}$

I have drawn the right angle triangle for visualization

equation for the line passing through (1,0) and (0,4) is

$\frac{y}{4} =\frac{x-1}{-1}$

$y=4-4x$

= $\int_{0}^1\int_{0}^{4-4x} (x^{2}+y^{2})dydx$

= $\int_{0}^{1}(x^{2}+\frac{y^{3} }{3})dx$

= $\int_{0}^{1}(x^{2}(4-4x)+\frac{1}{3}(4-4x)^{3} )dx$

= $\int_{0}^{1}(\frac{-76}{3}x^{3} +68x^{2}-64x^{}+\frac{64}{3} )dx$

= $=(\frac{-76}{3} \frac{x^{4} }{4})+\frac{68}{3}x^{3}-32x^{2}+\frac{64}{3}x^{})$

$=\frac{17}{3}$

3 0

3 years ago

Determine the domain of 3x+2/x-4

Kaylis [27]

Since the x value can be changed to anything other than 4 (because then you would be dividing by 0 in x-4), the answer is: All real numbers except 4.

4 0

4 years ago

.<br> 2. Find the volume of the right cone.<br> 4 cm<br> 3 cm

Ainat [17]

Answer:

i dont get it please alaborate

Step-by-step explanation:

4 0

3 years ago