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Harrizon [31]
3 years ago
8

Solve for all possible values of x.

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
4 0

Answer:

Option d)  x = 25

Step-by-step explanation:

we have

\sqrt{x-9}+4=8

Solve for x

Subtract 4 both sides

\sqrt{x-9}+4-4=8-4

\sqrt{x-9}=4

squared both sides

(x-9)=(+/-)4^2

(x-9)=(+/-)16

Adds 9 both sides

x=9(+/-)16

x1=9(+)16=25

x2=9(-)16=-7

<u><em>Verify </em></u>

1) For x=25

\sqrt{25-9}=4

\sqrt{16}=4

4=4 ----> is true

therefore

x=25 is a solution

2) For x=-7

\sqrt{-7-9}=4

\sqrt{-16}=4

The radicand cannot be a negative number

therefore

x=-7 is not a solution

larisa [96]3 years ago
3 0

Answer:

x= 25

Step-by-step explanation:

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