Question

Solve for all possible values of x.

Answer 1

Answer:

Option d)  x = 25

Step-by-step explanation:

we have

$\sqrt{x-9}+4=8$

Solve for x

Subtract 4 both sides

$\sqrt{x-9}+4-4=8-4$

$\sqrt{x-9}=4$

squared both sides

$(x-9)=(+/-)4^2$

$(x-9)=(+/-)16$

Adds 9 both sides

$x=9(+/-)16$

$x1=9(+)16=25$

$x2=9(-)16=-7$

Verify

1) For x=25

$\sqrt{25-9}=4$

$\sqrt{16}=4$

$4=4$ ----> is true

therefore

x=25 is a solution

2) For x=-7

$\sqrt{-7-9}=4$

$\sqrt{-16}=4$

The radicand cannot be a negative number

therefore

x=-7 is not a solution

Answer 2

Answer:

x= 25

Step-by-step explanation: