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Vinil7 [7]
3 years ago
14

find the width of the rectangular prism if the volume is 165,000 the length is 100 mm and the height is 55 ​

Mathematics
1 answer:
scoundrel [369]3 years ago
3 0

Answer:

30 mm

Step-by-step explanation:

The volume of a rectangular prism is the product of its three dimensions. To find the missing dimension, divide the volume by the product of the two that are given:

(165000 mm^3)/((100 mm)(55 mm)) = 165000/5500 mm^3/mm^2 = 30 mm

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3 years ago
Simplify the ratio<br> 40 : 28<br> Please show work! If your able too :)
otez555 [7]

Answer:

10:7

Step-by-step explanation:

ratios are simply just like fractions!

this ratio (40:28) can be re-written as 40/28

now, you can simplify this to its lowest terms

40/28=20/14=10/7

first in those steps i re wrote the question, then divided by two, then divided by two again !

so, 40:28=10:7

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you can even check this by cross multiplying, since ratios are fractions

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8 0
3 years ago
Read 2 more answers
A student researcher compares the ages of cars owned by students and cars owned by faculty at a local state college. A sample of
diamong [38]

Answer:

The point estimate for the true difference between the population means is 0.13.

The 90% confidence interval for the difference between the true mean ages for cars owned by students and faculty is between -0.35 years and 0.61 years.

Step-by-step explanation:

To solve this question, before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When we subtract two normal variables, the mean is the subtraction of the means while the standard deviation is the square root of the sum of the variances.

A sample of 263 cars owned by students had an average age of 7.25 years. The population standard deviation for cars owned by students is 3.77 years.

This means that:

\mu_s = 7.25, \sigma_s = 3.77, n = 263, s_s = \frac{3.77}{\sqrt{263}} = 0.2325

A sample of 291 cars owned by faculty had an average age of 7.12 years. The population standard deviation for cars owned by faculty is 2.99 years.

This means that:

\mu_f = 7.12, \sigma_f = 2.99, n = 291, s_f = \frac{2.99}{\sqrt{291}} = 0.1753

Difference between the true mean ages for cars owned by students and faculty.

Distribution s - f. So

\mu = \mu_s - \mu_f = 7.25 - 7.12 = 0.13

This is also the point estimate for the true difference between the population means.

s = \sqrt{s_s^2+s_f^2} = \sqrt{0.2325^2+0.1753^2} = 0.2912

90% confidence interval for the difference:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = zs = 1.645*0.2912 = 0.48

The lower end of the interval is the sample mean subtracted by M. So it is 0.13 - 0.48 = -0.35 years

The upper end of the interval is the sample mean added to M. So it is 0.13 + 0.48 = 0.61 years.

The 90% confidence interval for the difference between the true mean ages for cars owned by students and faculty is between -0.35 years and 0.61 years.

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Answer:

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BECAUSE THERE IS 7 DAYS IN A WEEK

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