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Gre4nikov [31]
3 years ago
14

3. What is the area of the figure below?

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0

Step-by-step explanation:

Area of the figure below=

\frac{1}{2}  \times 4 \times (10 + 3)

\frac{1}{2}  \times 4 \times 13

2 \times 13

26 in ²

optionA

Westkost [7]3 years ago
6 0
Answer A 26 in square (2)
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Given :-

  • a² - 2a - b² = 0
  • 2b + 2ab = 0

To find :-

  • Value of a and b .

Solution :-

<u>Taking</u><u> </u><u>second</u><u> </u><u>equation</u><u>:</u><u>-</u>

  • 2b + 2ab = 0
  • 2b ( 1 + a ) = 0
  • 2b = 0 or (1+a) = 0
  • b = 0 , a = -1

<u>Substitute</u><u> </u><u>in </u><u>first </u><u>equation</u><u> </u><u>:</u><u>-</u><u> </u>

  • a² - 2a - b² = 0

<u>When </u><u>b </u><u>=</u><u> </u><u>0</u><u> </u><u>,</u>

  • a² - 2a - 0² = 0
  • a² - a = 0
  • a( a -1) =0
  • a = 0 , 1

<u>When </u><u>a </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>,</u>

  • (-1)² - 2*(-1) - b² = 0
  • 1 + 2 - b² = 0
  • b² = 3
  • b = ±√3

<u>Answer </u><u>:</u><u>-</u><u> </u>

  • a = 0,1 ; b = 0
  • a = -1 , b = ±√3
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2 years ago
Given the function f(x) = 2|x + 6| – 4, for what values of x is f(x) = 6?
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Answer:

x = -1 , - 11,

Step-by-step explanation:

| x | = x

|- x | = x

f(x) = 2 | x + 6 | - 4

x = - 1 , f( - 1) = 2 | - 1 + 6 | - 4 = 2 | 5 | - 4 = 10 - 4 = 6 , True

x = 1 , f( 1 ) = 2 | 1 + 6 | - 4 = 2 | 7 | - 4 = 14 - 4 = 10 , False

x = 11, f( 11 ) = 2 | 11 + 6 | - 4 = 2 | 17 | - 4 = 34 - 4 = 30 , False

x = - 11, f( - 11) = 2 | -11 + 6 | - 4 = 2 | - 5 | - 4 = 10 - 4 = 6 , True

x = 14 , f( 14 ) = 2 | 14 + 6 | - 4 = 2 | 20 | - 4 = 40 - 4 = 36 , False

x = -14 , f( - 14 ) = 2 | - 14 + 6 | - 4 = 2 | - 8 | - 4 = 16 - 4 = 12 , False

x = - 26 , f( - 26) = 2 | -26 + 6 | - 4 = 2 | -20 | - 4 = 40 - 4 = 36 , False

x = 26, f( 26 ) = 2 | 26 + 6 | - 4 = 2 | 32 | - 4 = 64 - 4 = 60 , False

                                                    OR

Given f ( x ) = 6

f( x ) = 2 | x + 6 | - 4

6  = 2 | x + 6 | - 4

6 + 4 = 2 | x + 6| - 4 + 4                 [ adding 4 to both sides ]

10 = 2 | x + 6 | + 0

5 = | x + 6 |                                    [ dividing both sides by 2 ]

- 5 =\  ( x+ 6) \ = 5\\\\                            [ \ | x | = a\  => \ -a \ =  x \ = a  \ ]

- 5 - 6 =  \ x + 6 - 6 \ = \ 5 - 6\\            [ \ subtracting \ by \ 6 \ ]

-11 = \ x \ =  - 1

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