Answer:
The height of the water is 
Step-by-step explanation:
step 1
Find the volume of the tank
The volume of the inverted right circular cone is equal to
we have
substitute
step 2
Find the 25% of the tank’s capacity
step 3
Find the height, of the water in the tank
Let
h ----> the height of the water
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional
substitute
where
r is the radius of the smaller cone of the figure
h is the height of the smaller cone of the figure
R is the radius of the circular base of tank
H is the height of the tank
we have
-----> volume of the smaller cone
substitute
Simplify
Let s be the scale factor then:
4s=10 and 6s=15
s=10/4 and s=15/6
s=5/2 and s=5/2
s=2.5
The scale factor is 2.5.
Answer:
I think the answer is x = 13/3
Step-by-step explanation:
(a) We use product rule here. P'(x) = F'(x)G(x) + F(x)G'(x).P'(2) = F'(2)G(2) + F(2)G'(2). Looking at the graph: F'(2) = 0, F(2) = 3, G'(2) = 1/2, G(2) = 2. Hence, P'(2) = (0)(2) + (3)(1/2) = 1.5.
(b) Using the quotient rule here. Q'(x) = (G(x)F'(x) - F(x)G'(x))/G(x)^2. Looking at the graph: F'(7) = 1/4, F(7) = 5, G'(7) = -3/2, G(7) = 1. Q'(7) = (1*1/4-5*(-3/2))/1^2 = 31/4 = 7.75.
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