Question

Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four , solve for f(g(x)) when x = 5. (1 point)

Answer 1

Rewrite g(x) as    x-1

                           ------

                              4

and then substitute this result for x in f(x) = x^2 - 3x + 3:

f(g(x)) = (x-1)^2 / 4^2 - 3(x-1)/4 + 3.

At this point we can substitute the value 5 for x:

f(g(5)) = (5-1)^2 / 4^2 - 3(5-1)/4 + 3

          = 16/16 - 3(4/4) + 3 = 1 - 3 + 3 = 1

Therefore, f(g(5)) = 1.