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Olegator [25]
3 years ago
6

Given: JL-tangent, LE-secantProve: LU·LE = LV·LK

Mathematics
1 answer:
irga5000 [103]3 years ago
8 0

Explanation:

By the properties of secants and tangents, ...

  LU·LE = LJ²

  LV·LK = LJ²

By the transitive property of equality, ...

  LU·LE = LJ² = LV·LK

  LU·LE = LV·LK

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