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deff fn [24]
3 years ago
5

1. What are foci? 2. What is the first step to take to write the equation of a hyperbola? 3. How do you represent parts of a hyp

erbola algebraically?
Mathematics
1 answer:
Andrei [34K]3 years ago
5 0

Answer:  see below

<u>Step-by-step explanation:</u>

1) Foci is plural for Focus.  Since a hyperbola has two focus points, they are referred to as foci.  The foci is where the sum of the distances from any point on the curve to the foci is constant.

2) When determining the equation of a hyperbola you need the following:

    a)  does the hyperbola open up or to the right?

    b)  what is the center (h, k) of the hyperbola?

    c)  What is the slope of the asymptotes of the hyperbola?

3) The equation of a hyperbola is:

\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1\qquad or\qquad \dfrac{(y-k)^2}{b^2}-\dfrac{(x-h)^2}{a^2}=1

  • (h, k) is the center of the hyperbola
  • ± b/a is the slope of the line of the asymptotes
  • The equation starts with the "x" if it opens to the right and "y" if it opens up

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Veronika [31]
Um not to sure about that
7 0
3 years ago
What is the value for y?<br> Enter your answer in the box.
lapo4ka [179]

Answer:

y = 14

Step-by-step explanation:

The sum of the angles in a triangle add to 180 degrees

50 + 2x+ 5y + 10 = 180

We know that 2x = 50 since they are the base angles of sides that have the same length, they must be the same

50 + 50 + 5y+10 =180

Combine like terms

110 + 5y =180

Subtract 110 from each side

110+5y-110 = 180-110

5y = 70

Divide each side by 5

5y/5 =70/5

y = 14

6 0
2 years ago
Read 2 more answers
PLSSS HELP IF YOU TURLY KNOW THISS
vladimir2022 [97]
0.62
Should be correct
6 0
2 years ago
In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=4 and BC=3, Find AH, CH and BH.
IRISSAK [1]

Answer:

  • AH = 3.2
  • CH = 1.8
  • BH = 2.4

Step-by-step explanation:  

It can be convenient to compute the length of the hypotenuse of this triangle (AC). The Pythagorean theorem tells you ...

   AC^2 = AB^2 + CB^2

   AC^2 = 4^2 + 3^2 = 16 + 9 = 25

   AC = √25 = 5  

The altitude divides ∆ABC into similar triangles ∆AHB and ∆BHC. The scale factor for ∆AHB is ...

  scale factor ∆ABC to ∆AHB = AB/AC = 4/5 = 0.8  

And the scale factor to ∆BHC is ...  

  scale factor ∆ABC to ∆BHC = BC/AC = 3/5 = 0.6  

Then the side AH is 0.8·AB = 0.8·4 = 3.2

And the side CH is 0.6·BC = 0.6·3 = 1.8  

These two side lengths should add to the length AC = 5, and they do.  

The remaining side BH can be found from either scale factor:    

  BH = AB·0.6 = BC·0.8 = 4·0.6 = 3·0.8 = 2.4

_____  

The sides of interest are ...  

  AH = 3.2

  CH = 1.8

  BH = 2.4

3 0
3 years ago
You give up a full-time salary of $45,000 a year to go to school for 2 years. The total cost of going to school is $30,000. If y
Sloan [31]
I say that answer would be C:

2 years of lost wages 
(45K+45K) = 90K 
TOTAL cost of school = 30K 

sum of investment 
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5 years to recover investment 
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Salary plus amount required to recover investment 
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I hope my answer has come to your help. God bless and have a nice day ahead!</span>
5 0
3 years ago
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