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Bond [772]
2 years ago
5

If the square root of 61 is the longest side length in the triangle and the shorter sides are x and x+1, find the value of x tha

t makes the triangle above a right triangle. Write your answer in simplest radical form.
Mathematics
1 answer:
Tju [1.3M]2 years ago
5 0

Answer:

  x = 5

Step-by-step explanation:

You want to find x such that ...

  x^2 +(x +1)^2 = 61

  2x^2 +2x -60 = 0 . . . . . simplify, subtract 61

  x^2 +x -30 = 0 . . . . . . . divide by 2

  (x +6)(x -5) = 0 . . . . . . . . factor; solutions will make the factors be zero.

The relevant solution is x = 5.

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Given g(x)=3x−2find the value of g(2)
nevsk [136]

Answer:

The answer is 4

Step-by-step explanation:

g(x)=3x-2

g(2)=3*2-2=6-2=4

5 0
3 years ago
Use the function below to find f(4). F(x) = 3x
Sonja [21]
Since F(X) = 3^X,

F(4) = 3^4 = 81
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3 years ago
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A small pebble has a mass of<br> about<br> 20 L<br> b.<br> 20 ml<br> 20 g<br> 20 kg<br> d.
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7 0
3 years ago
Equation with a slope of -2 and point of (4,7)
s344n2d4d5 [400]

Answer:

y=-2x+15

Step-by-step explanation:

So first we can write it in point slope form.

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3 0
3 years ago
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Find x for equation 10 points
alexgriva [62]

Hi!

3x - 30 = x + 10

<h3>Solve by isolating x on one side. </h3><h3>Add 30 to both sides. </h3>

3x - 30 + 30 = x + 10 + 30

3x = x + 40

<h3>Subtract x from both sides. </h3>

3x - x = x - x + 40

2x = 40

<h3>Divide by 2 on both sides</h3>

2x/2 = 40/2

<u>x = 20</u>

<h2>The answer is x = 20</h2>

Hope this helps! :)

-Peredhel

6 0
3 years ago
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