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dedylja [7]
4 years ago
14

What point divides the directed line segment ​ AB¯¯¯¯¯ ​ ⁢ into a 3:1 ratio?

Mathematics
1 answer:
madam [21]4 years ago
4 0

Answer:

The ratio is 3.7

Step-by-step explanation:

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Discount:36% sale price:32 what is the original price?
siniylev [52]
Sale Price = 100% - 36% = 64%

Sale Price is $32
64% = $32

-------------------------------------
Find 1 % :
-------------------------------------
64% = $32
1% = $0.50

-------------------------------------
Find 100% (Original Price) :
-------------------------------------
1% = $0.50
100% = $0.50 x 100
100% = $50

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Answer: The original Price is $50.
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3 0
3 years ago
Given the function f(x)=8x+2, evaluate f(6)
ddd [48]
F(x)=8x+2
f(6)=8(6)+2
f(6)=48+2
=50
5 0
3 years ago
rita is estimating the height of her office building. The actual height of her office building is 10.7 m. Rita's estimate is 11
ddd [48]
La estimacion de Rita tiene un margen de error de 3% pero si lo vemos del modo de que esta redondeando la respuesta es correcta plisssss dame respuesta mas inteligente la necesito para subir de nivel
3 0
3 years ago
find the x-intercepts and the coordinates of the vertex for the parabola Y equals negative X squared plus 8X -12. If there’s mor
Oksanka [162]

Answer:

x = 2, and 6

x = 2 , 6

Step-by-step explanation:

The quadratic function to analyze is: y = -x^2+8x-12

In order to find where the corresponding parabola intercepts the x axis, we set it equal to zero (y = 0):

y = -x^2+8x-12\\0 = -x^2+8x-12\\x^2-8x+12=0

This equation is easy to solve by factoring. We look for a air of integer numbers whose product equals the constant term "12", and whose combinig renders the coefficient of the middle term of the trinomial "-8".

The two such numbers are "-2" and "-6". We use them to split the middle term, and then solve by factoring by grouping:

x^2-8x+12=0\\x^2-2x-6x+12=0\\(x^2-2x)+(-6x+12)=0\\x(x-2)-6(x-2)=0\\(x-2)(x-6)=0

For the product of two factors to render zero, we need either one to be a zero.This means that (x-2)=0 (that is x = 2), or (x-6)=0 (that is x = 6).

So, there are two x-intercepts: x= 2, and 6

3 0
3 years ago
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v>=2i-4tj^
guapka [62]

Given :

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj  .

To Find :

A. The vector position of the particle at any time t .

B. The acceleration of the particle at any time t .

Solution :

A )

Position of vector v is given by :

d=\int\limits {v} \, dt\\\\d=\int\limits {(2i-4tj)} \, dt \\\\d=(2t)i+\dfrac{4t^2}{2}j\\\\d=(2t)i+(2t^2)j

B )

Acceleration a is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{2i-4tj}{dt}\\\\a=\dfrac{2i}{dt}-\dfrac{4tj}{dt}\\\\a=0-4j\\\\a=-4j

Hence , this is the required solution .

5 0
3 years ago
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