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dedylja [7]
4 years ago
14

What point divides the directed line segment ​ AB¯¯¯¯¯ ​ ⁢ into a 3:1 ratio?

Mathematics
1 answer:
madam [21]4 years ago
4 0

Answer:

The ratio is 3.7

Step-by-step explanation:

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Risa is sewing around the side of a square each side of the blanket is 72 inches long h many inches of ribbon will rise need
Dennis_Churaev [7]
288 ; 72 x 4 = 288.
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3 years ago
Two large and 1 small pumps can fill a swimming pool in 4 hours. One large and 3 small pumps can also fill the same swimming poo
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It would take you 5/3 hours, or 1 hour and 40 minutes.

Hope I helped! ☺

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3 years ago
Choose all statements that show correct reasoning for finding 15 divided by 2/9
skelet666 [1.2K]

Answer:

The second and the last options.

Step-by-step explanation:

15/ 2/9 =67.5 Solve the original problem

15*2/9 =3.33333333333

15*9/2 =67.5

(15* 1/9) /2=0.833333333333333

15*9* 1/2 =67.5

8 0
3 years ago
Read 2 more answers
In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir
Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}= p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0204^{2}).

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.96

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0306^{2}).

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.31

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0
3 years ago
3) INITII equation y=-x+ 4<br> equation<br> W10<br> slope (m) = _<br> y-intercept =
vodomira [7]

Answer:

slope (m) = 1 and intercept = -4

Step-by-step explanation:

comparing with Y = mX - c

4 0
3 years ago
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