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Nookie1986 [14]
3 years ago
7

How do you solve for y?

Mathematics
2 answers:
Lyrx [107]3 years ago
8 0
Lets solve your equation.

30 = -5/4y

step 1: Flip Equation

-5/4y =30

Step 2: Multiply both sides by 4/(-5)
(4/-5)*(-5/4y) = (4/-5)*30

y = - 24

Answer: y = - 24

there you go.
Rashid [163]3 years ago
6 0
Hi there!

In order to solve for y, we need to divide each side by -5/4.

30 ÷ -5/4
= 30 × -4/5
= -120/5
= -24

y = -24

Hope this helps!
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KonstantinChe [14]

Answer:

Slope is -4

Y-intercept is -3 or (0, -3)

Step-by-step explanation:

y= mx + b

m = slope

b = y-intercept

12x + 3y = -9

3y = -12x - 9

y = -4x - 3

6 0
3 years ago
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Find the missing side lengths.<br><br> Can someone please help???
ale4655 [162]

Answer:

x = sqrt (2), y = sqrt (2)

Step-by-step explanation:

Here is how we can approach this problem in a step by step solution:

  1. Look at what we are given - we know that the triangle is a right triangle (has a square on one of its angles representing 90 degrees), and the hypotenuse (the side opposite 90 degree angle) is 2 units long, and one of the other angles is 45 degrees
  2. Using this information about angle measurements, we can solve for the third angle using the sum of angles in a triangle equals 180 degrees theorem: 180 - 90 - 45 = 45. After solving, we get that the final angle is 45 degrees
  3. Now, we know that the angles of the triangle are 90, 45, and 45 degrees. Using the base angle theorem, we know that his triangle must be an isocoles right triangle
  4. That means that both legs of the triangle must be congruent (x = y)
  5. Finally, we can use the Pythagorean theorem because this is a right triangle to solve for the missing sides 4 = x^2 + y^2, 4 = 2 + 2, x = sqrt (2) y = sqrt (2)

*Also, if you knew that a 45-45-90 triangle's sides form a ratio of a, a, and sqrt (2) a, you could also use that and substitute in the values to solve. Both ways work! Hope this helps!!

6 0
3 years ago
Help with number 3 please
iren2701 [21]

Answer:

35.26

Step-by-step explanation

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4 years ago
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RS=2x-8, ST = 11, RT = x+10
ziro4ka [17]

Answer:

Equation~=~\Large\boxed{2x+3=x+10}

x~=~\Large\boxed{7}

RS~=~\Large\boxed{6}

RT~=~\Large\boxed{17}

Step-by-step explanation:

<u>Given information</u>

RS=2x-8

ST=11

RT=x+10

<u>Derived expression from the given information</u>

<em>Presumably, I think this is a combination of segments</em>

RS+ST=RT

<u>Substitute values into the given expression</u>

(2x-8)+(11)=(x+10)

<u>Combine like terms</u>

<em>The following is the expression</em>

\Large\boxed{2x+3=x+10}

<u>Subtract 3 on both sides</u>

2x+3-3=x+10-3

2x=x+7

<u>Subtract x on both sides</u>

2x-x=x+7-x

\Large\boxed{x=7}

<u>Substitute the x value into corresponding expressions to determine the final value</u>

RS=2x-8=2(7)-8=14-8=\Large\boxed{6}

RT=x+10=(7)+10=\Large\boxed{17}

Hope this helps!! :)

Please let me know if you have any questions

3 0
2 years ago
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