Answer:
Both air balloon and water balloon data are best modeled by an exponential function.
Step-by-step explanation:
Air balloon
Time (seconds) Volume (cubic centimeters)
0 95
3 69
6 50
9 37
12 27
The relation Volume variation/time is constant for lines, In this case, this value change from point to point, as can be seen next.
(69 - 95)/3 = -8.67
(50 - 69)/3 = -6.33
(37 - 50)/3 = -4.33
(27 - 37)/3 = -3.33
Water balloon
Time (seconds) Volume (cubic centimeters)
0 30
3 15.8
6 7.8
9 4
12 2
(30 - 15.8)/-3 = -4.73
(15.8 - 7.8)/-3 = -2.67
(7.8 - 4)/-3 = -1.27
(4 - 2)/-3 = -0.67
In this case, the relation Volume variation/time also change from point to point.
Then, both air balloon and water balloon data are best modeled by an exponential function.
Answer: 9/15 < 10/15
Step-by-step explanation: 9/15 < 10/15
Answer:
The last 1 (D)
Step-by-step explanation:
The lines have to be straight nd have to pass through the origin
Easy, subsitute a point
we see it goes through (0,4)
so subsitte 0 for x and see if we get 4
4^0=1, nope
4^0-3=1-3=-2, nope
4^0+3=1+3=4, yep
4^(0+3)=4^3=64, noe
answer is 3rd option
f(x)=4^x+3
