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steposvetlana [31]
3 years ago
14

52 = 1/2* (190 - 2x)

Mathematics
1 answer:
Degger [83]3 years ago
6 0
Are these two seperate equations or the same one???
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A population grows with an annual growth rate of 16.5 % per year. (a) what is the monthly growth rate
Shtirlitz [24]
The monthly growth rate would be 16.5% divided by 12 which is 1.3%
8 0
3 years ago
A circle has a circumference of 615.44 point, 44 units.<br> What is the radius of the circle?
Tpy6a [65]

The circumference of a circle is equal to C=2πr

From the question, we have 615.44.

Assume that pi is equal to 3.14

Substitute and solve for r

615.44= 2(3.14)r

r= 615.44/ 6.28

r=98.4704

r=98

Therefore, the radius is about 98 units.

To check:

C=2πr

C=2 x 3.14 x 98

C=6.28 x98

C=615.44

5 0
3 years ago
Si multiplicó una ecuación de grado 2 con una ecuasion de grado 3 ¿Cuál es el grado de la ecuación resultante? ​
leonid [27]
English? Do you know how to speak English
6 0
4 years ago
Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

7 0
3 years ago
2x-5) = 2(x-5) One Solution Infinitely Many Solutions No Solution 5x + 4) = 5(1-6) 5(x + 4) = 3(x-6) 4x - 2) = 4(x + 2) x + 2(x-
Gekata [30.6K]

9514 1404 393

Answer:

  top down: ∞, 0, 1, 0, ∞

Step-by-step explanation:

The equation will have infinite solutions when the left side and right side simplify to the same expression. This is the case for the first and last expressions listed.

  2(x -5) = 2(x -5) . . . . expressions are already identical

  x +2(x -5) = 3(x -2) -4  ⇒  3x -10 = 3x -10 . . . the same simplified expression

__

The equation will have no solutions when the x-coefficients are the same, but there are different added constants.

  5(x +4) = 5(x -6)  ⇒  x +4 = x -6  . . .  not true for any x

  4(x -2) = 4(x +2)  ⇒  x -2 = x +2  . . .  not true for any x

__

The equation will have one solution when coefficients of x are different.

  5(x +4) = 3(x -6)  ⇒  2x = -38  ⇒ x = -19

4 0
3 years ago
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