#1:
A)
you need to know where a vertex goes on a isosceles triangle...
I attached a picture that explains it.....
you also want to label triangle.... XYZ
I put a picture on of how you should of labeled the triangle...
B)
so we need to find Measure for each angle.... REMEMBER: A triangle angles needs to = 180.
so your equations will need to be equal to 180.
4x+4+2x+2+7x-8=180
so we combine liked terms
4x+2x+7x=13x
4+2-8=-2
13x-2=180
+2 +2
13x=182
/13 /13
x=14
now you plug in X
4(14)+4= 60
2(14)+2= 30
7(14)-8= 90
now you want to check you answers so add them up to see if your answers equal 180...
60+30+90=180
to be continued.... i do second question on a second answer since i dont want pictures to get mixed up
Answer:
Elements in third column = - (elements in the first column) + 8(elements in the second column)
Step-by-step explanation:
A matrix is a rectangular array in which elements are arranged in a rows and columns.
Order of a matrix = Number of rows × Number of columns
Given matrix is
Here,
So,
Elements in third column = - (elements in the first column) + 8(elements in the second column)
The correct option is (b) h=0.5cos(/6t)+9.5.
The equations can be used to model the height as a function of time, t, in hours is h=0.5cos(/6t)+9.5.
The following is a presentation of the cosine function's generic form;
y = a + cos(bx - c) + d
amplitude = a
b = cycle speed
Calculation for the model height;
The height, h (feet) of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet.
Obtain amplitude 'a' as
The time 'T' is calculated as-
Now, calculate 'd'
Therefore, with the height as a function of time, t, expressed in hours, can be modeled by the following equations:
h=0.5cos(/6t)+9.5
To know more about the general equation of a cosine function, here
#SPJ4
The complete question is-
The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equations can be used to model the height as a function of time, t, in hours? Assume that the time at t = 0 is 12:00 a.m.
A. h=0.5cos(/12t)+9.5
B. h=0.5cos(/6t)+9.5
C. h=cos(/12t)+9
D. h=cos(/6t)+9