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4 years ago

Consider this scatter plot.

Mathematics

1 answer:

Radda [10]4 years ago

4 0

Answer:

Positive correlation

5 hours yield a score of 76

41 is the test score for no hours of study

Step-by-step explanation:

There is a positive correlation because the more hours spent on homework the better the test score generally it.

Use the function y=7x+41 by substituting x=5 and simplifying to predict the test score.

y=7(5)+41

y=35+41

y=76

The number 41 is the y-intercept and starting value. This means with 0 hours of study you are likely to score a 41 on the test.

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PLEASE HELP ASAP FOR 10 POINTS

luda_lava [24]

Answer:

x^4 - 16.

Step-by-step explanation:

This is simplified as follows:

(x^2 + 4)(x^2 - 4)

= x^4 - 16 ( by 'the difference of 2 squares').

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3 years ago

Alison made a three-layer gelatin dessert that was 15 cm long by 10 cm wide. The heights of the layers were 3 cm,

leonid [27]

Answer:

600 cm sq

Step-by-step explanation:

1 15 times 10 times 3= 450

2 15 times 10 times 2= 300

3 15 times 10 times 1 = 150

4 Add all your answers and get 600 cm sq

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3 years ago

Read 2 more answers

In triangle pqr, point c is the centroid. if pc = 9, then PY =

aliya0001 [1]

Answer:

centroid divides median into the ratio 2:1 then

PC/CY=9/x=2/1

x=4.5

then the total length PY = 9+4.5=13.5

3 0

4 years ago

Who can help me ????.<br>instruction find the missing length.

djverab [1.8K]

Answer:

19 is the answer i think.

7 0

3 years ago

Find the point P on the line yequals=33x that is closest to the point (60 comma 0 )(60,0). What is the least distance between P

scoray [572]

Answer:

$18\sqrt{10}$ units$

Step-by-step explanation:

We are given the equation of the line y=3x and a point, say Q(60,0) outside of that line.

We want to find the point on the line y=3x which is closest to Q.

Let P(x,y) be the desired point. Since it is on the line y=3x, it must satisfy the line.

If x=a, y=3a, so the point P has the coordinates (a,3a).

Distance between point Q and P

$=\sqrt{(60-a)^2+(0-3a)^2}\\D =\sqrt{10a^2-120a+3600}$

To minimize D, we find its derivative

$\dfrac{dD}{da}=\dfrac{10a-60}{\sqrt{10a^2-120a+3600} }\\$Setting \dfrac{dD}{da}=0\\10a-60=0\\10a=60\\a=6$

Therefore, the y-coordinate for P is 3*6=18.

The point P=(6,18).

Next, we calculate the distance between P(6,18) and (60,0).

$D =\sqrt{10(6)^2-120(6)+3600}\\=\sqrt{3240}\\=18\sqrt{10}$ units$

8 0

4 years ago