The answer is C. We can suppose that the Grey gene is "A" and Black gene is "a". So the gene of heterozygous grey fruit fly is "Aa", and the black-bodied fruit fly is "aa". After mating, the offspring can get only "a" from balck-bodied fruit fly and has equal opportunity to get a "A" or "a" from heterozygous grey fruit fly. If the gene of offspring is "Aa", it will be grey. If "aa", it will be black. So the proportion of being black is 0.5.
One of the many tests that may be used to identify the presence of cyclohexanol in a product is that of the Lucas test.
The Lucas test is a chemical reactant test to determine the presence and level of alcoholism in a solution. Cyclohexanol has many chemical properties as do most substances, one of which is the presence of an alcohol group.
The presence of this chemical group makes it possible to test for cyclohexanol using the Lucas test. The Lucas test will cause reactions in the presence of alcohol and transform alcohols into chloroalkanes, which tend to be nearly insoluble in aquatic solutions. Given this, a <u>positive result </u>will look like <em><u>the solution separates into a cloudy chloroalkane-containing part on top of a much clearer layer.</u></em>
To learn more visit:
brainly.com/question/7141113?referrer=searchResults
Structural adaptations<span> are physical features of an </span>organism<span> like the bill on a bird or the fur on a bear. Other </span>adaptations<span> are behavioral. Behavioral </span>adaptations<span> are the things </span>organisms do<span> to </span>survive. For example, bird calls and migration are behavioraladaptations<span>.</span>
