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Volgvan
3 years ago
7

What event must take place during interphase before a cell proceeds to division?

Biology
1 answer:
Roman55 [17]3 years ago
4 0

Replication of the DNA  

Typically, growth too

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Answer: D

Explanation:

The oven probably isn’t cooking right because the temperature strength is not as strong as the average oven.

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2 years ago
Which statement most completely describes the primary role of the cell in a multicellular organism?
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Answer:

A

Explanation:

Since we know that the multicellular organism has the basic roles of living,growing and reproducing its genetic matieral enables it to do each of the following.

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Forest rangers are genetically testing the deer in the forest after many were found dead. The tests determined that due to inbre
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they need to introduce new deer and won't the earth worms and other such primary consumers will thrive because the deer are not there to eat them

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3 years ago
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How does coral reef damage negatively affect the land? a.) There is more biodiversity. b.) There is a loss of cures. c.) There i
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C. There is more land erosion

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3 years ago
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In 1985 a biologist counted 750 pine trees in a 250 hectare forest. Using similar counting techniques, the biologist counted 1,2
Alisiya [41]

Answer:

Suppose that we have a given function f(x)

The average rate of change of the function between two values x₁ and x₂ is given by:

r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}

a) We want to find the average (rate) of change on the size of population from 1985 to 1995.

We have that:

f(1985) = 750

f(1995) = 1500

Then we have:

r = \frac{1500 - 750}{1995 - 1985}  = 750/10 = 75

This means that the population of trees increases, in average, at a rate of 75 trees per year.

b) What is the density of trees each year that they were counted?

This will be equal to the quotient between the number of trees and the area.

1985: number of trees = 750 pines

         area = 250 ha

Then the density is:

D(1985) = (750 pines)/(250 ha) = 3 pines/ha

So 1985, there were 3 pines per hectare.

1990: number of trees = 1250 pines

         area = 250 ha

Then the density is:

D(1990) = (1250 pines)/(250 ha) = 5 pines/ha

1995: number of trees = 1500 pines

         area = 250 ha

The density is:

D(1995) = (1500 pines)/(250 ha) = 6 pines/ha

3) now we want to get the average change between 1985 and 1995 in the density, this will be:

r = \frac{D(1995) - D(1885)}{1995 - 1985}  = \frac{6 pines/ha - 3pines/ha}{10}  = 0.3 pines/ha

So, on average, each year the number of pines per hectare increases by 0.3

7 0
3 years ago
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