To find the answer, subtract j(x) from g(x):
g(x) - j(x)
Plug in the expressions that each function is equal to:
(x^2 - 2x + 11) - (-x^3 - 4x^2 + 5)
Distribute the negative, get rid of parentheses:
x^2 - 2x + 11 + x^3 + 4x^2 - 5
Combine like terms:
x^3 + 5x^2 - 2x + 6
Synthetic division yields
-3 | 1 5 4 -6
. | -3 -6 6
- - - - - - - - - - - - -
. | 1 2 -2 0
which translates to
with remainder 0. Now by the quadratic formula,
and so
Solve the equation of the function for n.
a(n) = 3n - 20
a = 3n - 20
a + 20 = 3n
(a + 20)/3 = n
n = (a + 20)/3
n(a) = (a + 20)/3
Answer:
2 Paul's Survey sample only included tenth graders
Step-by-step explanation:
The reson why this is your answer is simple
Because this is true, he ONLY surveyed tenth-graders. He should have found for all of the students, including the other 1,100 students that didn't get surveyed.
Thanks!
I hope this is right i think the answer is 40
