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likoan [24]
3 years ago
8

Find the roots. 3x2 - 5x+ 2 =0

Mathematics
1 answer:
tigry1 [53]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

Given

3x² - 5x + 2 = 0

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term

product = 3 × 2 = 6 and sum = - 5

The factors are - 3 and - 2

Use these factors to split the x- term

3x² - 3x - 2x + 2 = 0 ( factor the first/second and third/fourth terms )

3x(x - 1) - 2(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(3x - 2) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

3x - 2 = 0 ⇒ 3x = 2 ⇒ x = \frac{2}{3}

Roots are x = 1, x = \frac{2}{3}

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2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16
Masja [62]

Answer: \frac{x-4}{2x-2}

Step-by-step explanation:

\frac{2x^2+5x+3}{x^2-3x-4} divided by \frac{4x^2+2x-6}{x^2-8x+16} is the same thing as multiplying \frac{2x^2+5x+3}{x^2-3x-4} by \frac{x^2-8x+16}{4x^2+2x-6}.

The equation we get is:

\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}

With this equation, we can factor each equation:

\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}

We can cancel out like terms since they would be dividing each other:

\frac{x-4}{2x-2}

8 0
3 years ago
Plz help<br> Will mark brainliest
Alexandra [31]

Answer:

(0,-1)

Step-by-step explanation:

(0,-1) will work because when you plug them is it is equivalent to 4

6 0
3 years ago
Please help me with this problem
Naya [18.7K]

Answer:

Dasha has 52 roses

Step-by-step explanation:

Rewrite the first sentence in an equation: (D= Dasha) (A= Anna)

D=4A

Rewrite the second sentence in an equation:

A+39=D

1) Substitute A+39 as D in the first equation:

A+39=4A

2) Subtract A from both sides:

3A=39

3) Divide both sides by 3:

A=13

4) Now substitute 13 as A in the second equation:

13+39=D

5) Solve:

D=52

4 0
3 years ago
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Solnce55 [7]
What u not sure bout?
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4 years ago
What is the midpoint of (3,8) and (6,4)
Andrews [41]

(4.5,6) that is what i got.

4 0
3 years ago
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