Question

F(n)=5xf(n-1)f(0)=5f(3)= (x means multiple)

Answer 1

Answer:

625

Explanation:

So this says the following:

A term is equal to 5 times the previous term.

We are given the 0th- term is 5.

The first term is 5(5)=25.

The second term would be 5(25)=125.

The third term would be 5(125)=625.

So f(3)=625.

If you didn't like that explanation, you can find f(3), by first finding f(1) then f(2) using the equation given as is without making the interpretation I did above.

$f(n)=5 \cdot f(n-1)$ ; plug in 1 for $n$:

$f(1)=5 \cdot f(1-1)$

$f(1)=5 \cdot f(0)$

$f(1)=5 \cdot 5$

$f(1)=25$

$f(n)=5 \cdot f(n-1)$ ; plug in 2 for $n$:

$f(2)=5 \cdot f(2-1)$

$f(2)=5 \cdot f(1)$

$f(2)=5 \cdot 25$

$f(2)=125$

$f(n)=5 \cdot f(n-1)$ ; plug in 3 for $n$:

$f(3)=5 \cdot f(3-1)$

$f(3)=5 \cdot f(2)$

$f(3)=5 \cdot 125$

$f(3)=625$

Answer 2

Answer:

$\displaystyle 625$

Explanation:

All results are quintupled the previous terms:

$\displaystyle 5 = f(0) \\ 25 = f(1) \\ 125 = f(2) \\ 625 = f(3)$

I am joyous to assist you anytime.