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dalvyx [7]
3 years ago
15

Finding an Indefinite Integral dx/x(lnx^2)^3

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
3 0

Step-by-step explanation:

Firstly, we'll try to simplify the integrand. By hint 1, we see that:

\ln(x^2) = 2\ln(x)

Simplifying the integrand gives us:

\frac{1}{8}\left(\frac{1}{x(\ln(x))^3}\right)

Next, by hint 2, we observe that:

\frac{d}{dx}\left(\ln(x)\right) = \frac{1}{x}

So this tells us to make the substitution: u = \ln(x)

Doing so gives us:

\int \frac{dx}{x(ln(x^2))^3} = \int \frac{du}{8u^3}, which should be trivial.

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the combined age of april and laura is 23 years. laura's age is two years more than half of april's age. what is laura's age
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Laura's age is 9 years.

Solution:

Let x be the age of April.

Laura's age = 2 years more than half of April's age

<u>Convert statement into algebraic expression:</u>

Half of April's age = \frac{x}{2}

2 years more than half of April's age = \frac{x}{2}+2

Combined age of April and Laura = 23

⇒ April's age + Laura's age = 23

$\Rightarrow \ \ x+(\frac{x}{2}+2) =23

$\Rightarrow \ \ x+\frac{x}{2}+2 =23

$\Rightarrow \ \ \frac{x}{1}+\frac{x}{2}+\frac{2}{1} =23

To add the fractions make the denominators same.

Multiplying 2 on both numerator and denominator of unlike terms, we get

$\Rightarrow \ \ \frac{x\times2}{1\times2}+\frac{x}{2}+\frac{2\times2}{1\times2} =23

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$\Rightarrow \ \ \frac{2x+x+4}{2} =23

Do cross multiplication.

$\Rightarrow \ \ 2x+x+4=23\times2

$\Rightarrow \ \ 3x=46-4

$\Rightarrow \ \ 3x=42

$\Rightarrow \ \ x=14

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                    = 7 + 2

Laura's age = 9

Hence Laura's age is 9 years.

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